Lucas read 30% of his book containing 480 pages. What page is he going to read next?

The mean of Holly's first six math quiz scores was 75%. After taking the seventh quiz, her

lord [1]

The total of her first six quizzes is 75*6 = 450

Let her seventh score be x
The total of her seven quizzes be 450+x

Then, (450+x)/7 = 77
x = (77*7) - 450 = 89

Her seventh score is 89
x =

3 0

3 years ago

Write a question that can be represented by the division equation 5 divided by 1 1/2

babunello [35]

Zog went to Elfos pie shop with 11 friends. He ordered 5 pie’s. How big do the slices need to be?

3 0

2 years ago

Order the following numbers from least to greatest.

GalinKa [24]

Answer:

Step-by-step explanation:

-24, 24, 48, 72

Hope this helps :)

5 0

2 years ago

If you deposit $1000 in a savings account with an interest rate of r compounded annually, then the balance in the account after

Sedaia [141]

Answer:

B

Step-by-step explanation:

Our equation is as follows, B(c)=1000(1+r)^3. We are being asked to manipulate the equation and have it be r equals in order to solve for an interest rate when given a balance B. To solve the equation for the variable r, we must isolate r by completing order of operations or PEMDAS backwards.

SADMEP allows us to undo subtraction, addition, and etc in the correct order. We have no subtraction or addition outside of more complex operations. So we move to multiplication or division.

We divide both sides by 1000.

$\frac{B}{1000} =\frac{1000(1+r)^{3} }{1000}$

We simplify the right side.

$\frac{B}{1000} =(1+r)^{3}$

We need to now undo the exponent of 3 by using the inverse, a cube root.

$\sqrt[3]{\frac{B}{1000}} =\sqrt[3]{(1+r)^{3}}$

We simplify the right side.

$\sqrt[3]{\frac{B}{1000}} =(1+r)$

We subtract 1 to both sides to get r alone.

$-1+\sqrt[3]{\frac{B}{1000}} =r$

For our last step, we simplify the denominator of the root because 10*10*10=1000.

$-1+\frac{\sqrt[3]{b} }{10} =r$

This is answer choice b.

5 0

3 years ago

Suppose that fund-raisers at a university call recent graduates to request donations for campus outreach programs. They report t

Flura [38]

Answer:

Following are the solution to the given points:

Step-by-step explanation:

In point a:

It's also expected that approximately $1000 \times 0.40 =400$ of both, the students contribute zero, approximately $1000 \times 0.30 =300$ to donors $10, approximately $1000 \times 0.25 = 250$ donors $25, and then about $1000 \times 0.05 = 500$ dollars $50 donors. Its frequencies would be similar to and not precisely, the probability. The four levels will stack up to a thousand.

In point b:

It is the population, in which the key value of x is a $0 donation ( 40 percent of students do this).

In point c:

$\to P(X \geq 25) \\\\\to 0.25+0.05 \\\\\to 0.30$

In point d:

$\to P(X>0)\\\\ \to 1-P(X=0)\\\\ \to 1- 0.40\\\\\to 0.60\\\\$

5 0

2 years ago