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vekshin1
2 years ago
11

How much wrapping paper is needed to cover a box (rectangular prism) that measures 6 feet by 2.5 feet by 3 feet?

Mathematics
1 answer:
AleksAgata [21]2 years ago
8 0

Answer:

81 feet ²

Step-by-step explanation:

Given that:

Dimension of rectangular prism :

6 feets by 2.5 feets by 3 feets

To obtain the amount of wrapping paper required to cover the box ; we find the area of the box ;

Area of box = 2(wl + hl + hw)

Area of box = 2(6*2.5 + 6*3 + 2.5*3)

Area of box = 2(15 + 18 + 7.5)

Area of box = 81 feet²

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\bold{\huge{\blue{\underline{ Solution}}}}

\bold{\underline{ We \: have \:given \: that, }}

  • <u>Distance </u><u>between </u><u>the </u><u>house </u><u>and </u><u>tower </u><u>is </u><u>3</u><u>5</u><u> </u><u>m</u>
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  • <u>The </u><u>height </u><u>of </u><u>the </u><u>house </u><u>is </u><u>2</u><u>5</u><u> </u><u>m</u>

\bold{\underline{ Now}}

  • <u> </u><u>Height</u><u> </u><u>of </u><u>the </u><u>house </u><u>is</u><u> </u><u>2</u><u>5</u><u>m</u>

\bold{\underline{ So, }}

\sf{ CE = 25m }

<u>Therefore</u><u>, </u>

\sf{ AB = AD - CE }

\sf{ AB = 60 - 25  }

\sf{ AB = 35 m }

<u>Now</u><u>, </u><u> </u><u>In </u><u>Right </u><u>angled </u><u>ABC</u>

\bold{tan Φ =}{\bold{\frac{ AB}{BC}}}

\bold{tan Φ =}{\bold{\frac{ 35}{35}}}

\bold{ tan Φ = 1 }

\bold{ tan Φ = 45 °}

\sf{\red{Hence, \: The \:angle \:of \:depression\: is \:45°}}

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