Answer:
Fractional probability of having 3 boys and 0 girls in a family for first 3 births is .
Step-by-step explanation:
Let A be the event of birth of a boy.
Let B be the event of birth of a girl.
Probability of birth of a boy, P(A)
Probability of birth of a girl, P(B)
We have to find the probability of birth of 3 boys i.e. event A occurring 3 times in a succession. It is independent events i.e. do not have any dependency on occurrence of any event.
So, Required probability can be calculated just by multiplying P(A) for 3 times.
i.e.
So, the probability of having 3 boys and 0 girls in the family is .
21Answer:
Step-by-step explanation:
Answer:
is A
Step-by-step explanation:
Answer:
$393.50+/-$19.72
= ( $373.78, $413.22)
Therefore, the 95% confidence interval (a,b) = ($373.78, $413.22)
Step-by-step explanation:
Confidence interval can be defined as a range of values so defined that there is a specified probability that the value of a parameter lies within it.
The confidence interval of a statistical data can be written as.
x+/-zr/√n
Given that;
Mean x = $393.50
Standard deviation r = $50.30
Number of samples n = 25
Confidence interval = 95%
z value(at 95% confidence) = 1.96
Substituting the values we have;
$393.50+/-1.96($50.30/√25)
$393.50+/-1.96($10.06)
$393.50+/-$19.7176
$393.50+/-$19.72
= ( $373.78, $413.22)
Therefore, the 95% confidence interval (a,b) = ($373.78, $413.22)
The answer is a, c, and e