Let the required equation be y = mx + c; where y = 1, m = f'(0), x = 0
f(a) = sec(a)
f'(a) = sec(a)tan(a)
f'(0) = sec(0)tan(0) = 0
y = mx + c
1 = 0(0) + c
c = 1
Therefore, required equation is
y = 1.
Answer:
pizzeria1
Step-by-step explanation:
Given data
pizzeria1
Diameter=16in
Radius= 16/2= 8in
Area= πr^2
Area= 3.132*8^2
Area= 201.09 in^2
pizzeria2
Diameter=15in
Radius= 15/2= 7.5in
Area= πr^2
Area= 3.132*7.5^2
Area= 176.74n^2
Answer:
the dark purple in the bottom, brown reddish one light purple one in the bottom
Step-by-step explanation:
Answer:
d. -7 1/8, -3.62, -1/2, 0, 1.75
Step-by-step explanation:
