For a cyclic quadrilateral
The opposite angles are supplementary (meaning they sum up to 180 °)
I.e (x +20) ° + 3x ° =180 °
20 + 4x = 180
4x=180 - 20
4x = 160
Divide through by 4
x = 40 °
Angle at point A
(2x + 38) = (2(40) + 38) = 118 °
Angle at point B
3x = 3(40) = 120 °
Angle at point D
x + 20 = 40 + 20 = 60 °
Angle at point C
The total angle in a quadrilateral is 360 °
I.e 118 + 120 + 298 +
-8-3=-5. there . thats the answer.
Answer:
Step-by-step explanation:
So, after you roll it, the width will be the circumference of the circle 
The minimum amount will be 
I don't know, how number you want to round, so you can round it by yourself
Answer:
x = 31.12
Step-by-step explanation:
First find the base (hypotenuse) of the smaller triangle (the isosceles triangle): Its three sides are 11, 11 and b. b can be found using the Pythagorean Theorem: b^2 = 11^2 + 11^2 = 242. Then b = √242, or b = approximately 15.56.
b (which is approximately 15.56) is the shorter leg of the large (right) triangle. The trig function needed to solve for x is the cosine:
adjacent side
cos 60 degrees = ----------------------
hypotenuse,
15.56
which becomes (1/2) = ------------
x
Solving this for x, we get: x = 2(15.56) = 31.12
