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I am Lyosha [343]
3 years ago
13

Pleaseee help im really confused

Mathematics
1 answer:
GuDViN [60]3 years ago
3 0

Answer:

431

Step-by-step explanation:

you take 7.75 divide it by 100 and then times it by 400

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Evaluate x+1 when x = 2.5
lina2011 [118]
Plug in 2.5 for x and you get

2.5+1 which equals 3.5
5 0
3 years ago
T/8 + 23 - 4 = 36. Solve for the variable. Write the answer only, do not type in T= form.
oksian1 [2.3K]
136 is the answer!!!!
6 0
3 years ago
A study sampled 350 upperclassmen (Group 1) and 250 underclassmen (Group 2) at high schools around the city of Portland. The stu
iVinArrow [24]

Answer:

-0.061 < P_1 -P_2< 0.025

Step-by-step explanation:

Give data:

n_1 = 350

n_2 =250

x_1 = 23

x_2 = 21

\hat{P} 1 = \frac{x_1}{n_1} = \frac{23}{350} = 0.066

\hat{P} 2 = \frac{x_2}{n_2} = \frac{21}{250} = 0.084

for 95% confidence interval

\alpha = 1 - 0.95 = 0.05 and \alpha/2 = 0.025

z_{\alpha/2} = 1.96  from standard z- table

confidence interval for P_1  and P_2 is

\hat{P} 1 - \hat{P} 2 \pm z_{\alpja/2} \sqrt{\frac{\hat{P} 1(1-\hat{P} 1)}{n_1} +\frac{\hat{P} 2(1-\hat{P} 2)}{n_2}}

(0.066 - 0.084) \pm 1.96 \sqrt{\frac{0.066(1-0.066)}{350} +\frac{0.084(1-0.084)}{250}}

-0.018 \pm 0.043

confidence interval is

-0.018 - 0.043 < P_1 -P_2

-0.061 < P_1 -P_2< 0.025

7 0
3 years ago
GUYS PLEASE HELP ME I REALLY DON'T UNDERSTAND THIS TASK!!!!!!! IT'S VERY IMPORTANT FOR ME!!!!! DISTANCE BETWEEN TWO TOWNSHIPS, E
Dimas [21]
For this problem, you know that the first walker will arrive 2 hours before the second, and increases his speed by 2 times the second walker. You also know there is a distance of 24 km. So up until some time x, the two walkers have to be going the same speed. If the first walker increases speed by two times the speed per hour, and arrives two hours earlier, then his initial speed will be 20 km/h, because after 2 hours, he will have an increase of 4 km/hr, and the second will have an increase of 2 km/h, thereby making the first arrive 2 hours earlier, if that makes sense.
5 0
3 years ago
Yochanan walked from home to the bus stop at an average speed of 5 km / h. He immediately got on his school bus and traveled at
kari74 [83]

Answer: 5 km walking and 30 km by bus

Step-by-step explanation:

Yochanan walked from home to the bus stop at an average speed of 5 km / h. He immediately got on his school bus and traveled at an average speed of 60 km / h until he got to school. The total distance from his home to school is 35 km, and the entire trip took 1.5 hours. How many km did Yochanan cover by walking and how many did he cover by travelling on the bus?

walking - 5km/h                                         bus - 60km/h

distance walking - d₁                                 distance bus - d₂

time walking - t₁                                         time bus - t₂

d₁ + d₂ = 35

t₁ + t₂ = 1.5

v = d/t

vwalking = d₁/t₁

5 = d₁/t₁ ⇒ d₁ = 5t₁

vbus = d₂/t₂

60 = d₂/t₂ ⇒ d₂ = 60t₂

d₁ + d₂ = 35 ⇒ 5t₁ + 60t₂ = 35

_________________________

5t₁ + 60t₂ = 35

t₁ + t₂ = 1.5  (*-5)

5t₁ + 60t₂ = 35

-5t₁ -5t₂ = -7.5   (+)

__________________________

55t₂ = 27.5

t₂ = 27.5/55 = 0.5 h

t₁ + t₂ = 1.5 ⇒ t₁ = 1.5 - 0.5 = 1h

d₁ = 5t₁ ⇒ d₁ = 5.1 = 5 km

d₂ = 60t₂ ⇒ d₂ = 30.0.5 = 30 km

6 0
3 years ago
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