Answer -864338
Step-by-step explanation:
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The solution (-4,2) satisfies for the system of linear equations 3x + 13y = 14; 6x + 11y = -2
<u>Step-by-step explanation:</u>
Step 1:
Given detail is the solution of the equations (-4, 2) ie, x= - 4 and y = 2
This implies that this solution should satisfy the given linear equations.
Step 2:
Substitute values of x and y in the equations and verify whether the right hand side equals the left hand side.
System 1 Eq(1) ⇒ LHS = 3(-4) + 13 (2) = -12 + 26 = 14 = RHS
System 1 Eq(2) ⇒ LHS = 6(-4) + 11(2) = -24 + 22 = -2 = RHS
Therefore, the first system of linear equations satisfy the condition.
<span>Answered by the following sums -
Outer square area = 4x^2
side of the square = 2x which is equal to diameter of circle == diameter of inner square.
radius of circle = x
diameter of outer square = 2*sqrt(2)*x
consider side of inner square = a
so a^2 + a^2 = (2x)^2
2a^2 = 4x^2
a = x*sqrt(2)
So area of inner square will be = 2x^2</span>
