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3 years ago

I NEED SMART MATH PEOPLE what are the values for the coefficiants and constant term of 0=2+3x^2-5x a= b= c=

Mathematics

1 answer:

Simora [160]3 years ago

7 0

3x^2-5x+2 = 0

So a = 3, b = -5, c = 2

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NO LINKS!!! Find the arc measure and arc length of AB. Then find the area of the sector ABQ.

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<u>Arc Measure</u>: equal to the measure of its corresponding central angle.

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$\textsf{Arc length}=2 \pi r\left(\dfrac{\theta}{360^{\circ}}\right)$

$\textsf{Area of a sector of a circle}=\left(\dfrac{\theta}{360^{\circ}}\right) \pi r^2$

$\textsf{(where r is the radius and the angle }\theta \textsf{ is measured in degrees)}$

<h3><u>Question 39</u></h3>

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Given:

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$\textsf{Area of the sector AQB}=\left(\dfrac{120^{\circ}}{360^{\circ}}\right) \pi (6)^2=12 \pi=37.70\:\sf ft^2\:(2\:d.p.)$

<h3><u>Question 41</u></h3>

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r = 12 cm
$\theta$ = 45°

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Arc AB = 45°

$\textsf{Arc length of AB}=2 \pi (12) \left(\dfrac{45^{\circ}}{360^{\circ}}\right)=3 \pi=9.42\:\sf cm\:(2\:d.p.)$

$\textsf{Area of the sector AQB}=\left(\dfrac{45^{\circ}}{360^{\circ}}\right) \pi (12)^2=18 \pi=56.55\:\sf cm^2\:(2\:d.p.)$

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