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posledela
3 years ago
14

A school needs to buy new notebook and desktop computers for its computer lab. The

Mathematics
2 answers:
Papessa [141]3 years ago
6 0

Answer:

$10750

275n+350d

hope this helps!!

Neporo4naja [7]3 years ago
6 0

Answer:

notebook computer= $5500

desktop computer= $5250

notebook and desktop computer= $10750

Step-by-step explanation:

First of all, we multiply $275 by 20 which would give you 5500. Next, we multiply 350 by 15 which gives you 5250. now to add the total number of notebook and desktop computers, we add them both, which results to 10750.

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Answer:

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3 years ago
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Find the measure of x and y
zysi [14]

Answer:

y - 41°

x - ?

Step-by-step explanation:

use method of Z equation

Z 41° so y is 41° too

make sense

8 0
3 years ago
A donation center has 44 small bins with 24 caned food in them they wanna give each food bank the same amount of food there are
denpristay [2]

Complete question :

A donation center has 44 small bins with 24 caned food in them they wanna give each food bank the same amount of food there are 4 food banks. How many cans should they give to each food bank?

Answer:

264 cans

Step-by-step explanation:

Number of bins = 44

Number of canned food per bin = 24

Total number of canned foods = (number of bins * number of canned food per bin)

Total number of canned foods = 44 * 24 = 1056

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Number of food per bank = 1056 / 4 = 264

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3 years ago
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AlladinOne [14]
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4 0
3 years ago
A random sample of n = 8 E-glass fiber test specimens of a certain type yielded a sample mean interfacial shear yield stress of
ANTONII [103]

Answer:

32.9-2.365\frac{4.9}{\sqrt{8}}=28.80    

32.9+2.365\frac{4.9}{\sqrt{8}}=37.00    

Step-by-step explanation:

Information given

\bar X=32.9 represent the sample mean for the sample  

\mu population mean (variable of interest)

s=4.9 represent the sample standard deviation

n=8 represent the sample size  

Confidence interval

The confidence interval for the mean is given by the following formula:

\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}   (1)

the degrees of freedom are given by:

df=n-1=8-1=7

Since the Confidence is 0.95 or 95%, the value of \alpha=0.05 and \alpha/2 =0.025, and the critical value for this cae would be t_{\alpha/2}=2.365

Now we have everything in order to replace into formula (1):

32.9-2.365\frac{4.9}{\sqrt{8}}=28.80    

32.9+2.365\frac{4.9}{\sqrt{8}}=37.00    

6 0
3 years ago
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