<span>Part A
</span>f(x)=30∗0.2xand<span>f(x)=45+3x</span><span>
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Part B</span>
f(x)=30+0.2(5)f(x)=45+3(5)<span>
Neighborhood A and neighborhood B both have 60 houses after 5 years
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Part C
1 year
A=36
B=48
2 years
A=42
B=51
3 years
A=48
B=54
4 years
A = 54
B = 57
5 years
A = 60
B= 60
Answer:
3x + 2y = 16
x = 2 , y = 5
Step-by-step explanation:
Given that George bought x quarts at $3.00 per quart & y quarts at $2.00 per quart and he bought 7 quarts for $16.00
Considering the total cost
3x + 2y = 16
For the cost of each
x + y = 7
solving the 2 equations simultaneously be substitution
x = 7 - y
3(7 - y) + 2y = 16
21 - 3y + 2y = 16
-3y + 2y = 16 - 21
-y = - 5
Divide both sides by -1
y = 5
x = 7 -y
x = 7 - 5
= 2
Answer:
m=5
Step-by-step explanation:
Let the number be represented by m.
Then twice the number m is represented as 2* m or 2m.
3 less than twice the number m = 2m -3
As per the question this value is 7.
Representing this in equation format:
=> 2m-3 = 7
=> 2m = 7+3 = 10
=> m= 10/2 = 5
Hence the number m is given by 5.
Verification:
Twice the number = 2* 5 = 10
3 less than twice the number m = 10 -3 = 7
This is the same as 7 as per the requirement.
I believe it’s 4,-4 and 3,-3 .
X=12
4x= 48
11x=132
(please give me brainliest)
