DE = AB, EF = BC and AC = DF, hence triangle ABC is congruent to triangle DEF.
<h3>
Congruent shape</h3>
Two shapes are said to be congruent if they have the same shape, all their corresponding angles and sides are congruent to one another.
Given that DE = AB and BC = EF.
In right triangle DEF, using Pythagoras:
DF² = DE² + EF²
Also, In right triangle ABC, using Pythagoras:
AC² = AB² + BC²
But DE = AB and EF = BC, hence:
AC² = DE² + EF²
AC² = DF²
Taking square root of both sides, hence:
AC = DF
Since DE = AB, EF = BC and AC = DF, hence triangle ABC is congruent to triangle DEF.
Find out more on Congruent shape at: brainly.com/question/11329400
Using a graphic tool.
<span>see attached graphic</span>
<span>
the solutions are
x1=-2
x2=0.811
</span>check
for x=-2
x^4+3x^3+3x2-3x-4
(-2) ^4+3(-2) ^3+3(-2) ^2-4=16+(-24)+12-4=0 ok
For x=0.811
(0.811) ^4+3(0.811) ^3+3(0.811) ^2-4=0.4326+(1.6002)+1.9731-4=0 ok
Answer:
It would increase by 1
Step-by-step explanation:
Step 1: Find the mean of the original
(9+6+1+1+3)/5 = 4
Step 2: Find the mean of the new
(9+6+1+1+8)/5 = 5
Step 3: Find the difference
5 - 4 = 1
Answer:
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Step-by-step explanation:
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Answer:
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Step-by-step explanation:
