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vlada-n [284]
3 years ago
12

Hey hun can any of y'all help me?

Mathematics
1 answer:
11111nata11111 [884]3 years ago
6 0
\bf \cfrac{5}{\frac{1}{6}+\frac{1}{x+1}}\qquad \cfrac{}{\impliedby LCD\textit{ will be 6(x+1)}}\implies \cfrac{5}{\frac{1(x+1)+1(6)}{6(x+1)}}
\\\\\\
\cfrac{5}{\frac{x+1+6}{6(x+1)}}\implies \cfrac{\frac{5}{1}}{\frac{x+7}{6(x+1)}}\implies \cfrac{5}{1}\cdot \cfrac{6(x+1)}{x+7}\implies \cfrac{30(x+1)}{x+7}

and you can expand the numerator if you wish, it won't be simplified further though.
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