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2 years ago

69 = 50 + s; 17, 18, 19

Mathematics

2 answers:

Sindrei [870]2 years ago

8 0

Answer:

Step-by-step explanation:

serious [3.7K]2 years ago

6 0

The answer is 19 pls mark brainliest if correct

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Write the number in 2 equivalent forms as a fraction, decimal, or percent. 11 16

pashok25 [27]

11.
Fraction - 11/100
Decimal - 0.11
Percent - 11%
16.
Fraction - 16/100
Decimal - 0.16
Percent - 16%

3 0

2 years ago

1.9(2.3n+6)+10.45>43.7

Ulleksa [173]

Answer:

4.27n+21.4

Step-by-step explanation:

8 0

2 years ago

Please see attachment

Dafna11 [192]

Answer:

a) The value of absolute minimum value = - 0.3536

b) which is attained at $x = \frac{1}{\sqrt{2} }$

Step-by-step explanation:

Step(i):-

Given function

$f(x) = \frac{-x}{2x^{2} +1}$ ...(i)

Differentiating equation (i) with respective to 'x'

$f^{l} = \frac{2x^{2} +1(-1) - (-x) (4x)}{(2x^{2}+1)^{2} }$ ...(ii)

$f^{l}(x) = \frac{2x^{2}-1}{(2x^{2}+1)^{2} }$

Equating Zero

$f^{l}(x) = \frac{2x^{2}-1}{(2x^{2}+1)^{2} } = 0$

$\frac{2x^{2}-1}{(2x^{2}+1)^{2} } = 0$

$2 x^{2}-1 = 0$

$2 x^{2} = 1$

$x^{2} = \frac{1}{2}$

$x = \frac{-1}{\sqrt{2} } , x = \frac{1}{\sqrt{2} }$

Step(ii):-

Again Differentiating equation (ii) with respective to 'x'

$f^{ll}(x) = \frac{(2x^{2} +1)^{2} (4x) - 2(2x^{2} +1) (4x)(2x^{2}-1) }{(2x^{2}+1)^{4} }$

put

$x = \frac{1}{\sqrt{2} }$

$f^{ll} (x) > 0$

The absolute minimum value at $x = \frac{1}{\sqrt{2} }$

Step(iii):-

The value of absolute minimum value

$f(x) = \frac{-x}{2x^{2} +1}$

$f(\frac{1}{\sqrt{2} } ) = \frac{-\frac{1}{\sqrt{2} } }{2(\frac{1}{\sqrt{2} } )^{2} +1}$

on calculation we get

The value of absolute minimum value = - 0.3536

Final answer:-

a) The value of absolute minimum value = - 0.3536

b) which is attained at $x = \frac{1}{\sqrt{2} }$

3 0

2 years ago

What is y=2x+1 3x+4y=26 equal?

strojnjashka [21]

Substitute in y= equation into 2nd equation to start.
(2,5)

7 0

2 years ago

Please help meeeeeee. image attached

Shtirlitz [24]

The midpoint between -4 and 8 is answer B) 2

8 0

2 years ago