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strojnjashka [21]
3 years ago
8

blake bought 6 light bulbs that contained 8 light bulbs each. he then used 14 of the light bulbs for his science project. how ma

ny of them are left?
Mathematics
2 answers:
maks197457 [2]3 years ago
8 0

Answer:

34

Step-by-step explanation:

you would multiply 6×8=48 then u subtract 48-14=34

Mekhanik [1.2K]3 years ago
3 0
34 light bulbs are left
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Can you guys help me asap
stepladder [879]
The answer should be D.
7 0
3 years ago
In 1997 there were 31 laptop computers at Grove High School. Starting in 1998 the school bought 20 more laptop computers at the
Kruka [31]

Using the linear equation, T = 20x + 31, the total number of computers at the end of 2005 is: C. 191.

<h3>How to Use a Linear Equation?</h3>

A linear equation is expressed as y = mx + b, where x is a function of y, m is the rate of change and b is the y-intercept or starting value.

In the scenario stated, we are given the linear equation for total number of laptop computers at the school after 1997 as, T = 20x + 31.

Rate of change = 20

y-intercept/starting value = 31

x = 2005 - 1997 = 8

To find the total number of laptop computers at Grove High School at the end of 2005 (T), substitute x = 8 into the equation, T = 20x + 31.

T = 20(8) + 31

T = 160 + 31

T = 191 computers.

Thus, total number of computers at the end of 2005 is: C. 191.

Learn more about linear equation on:

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7 0
2 years ago
Which statement best describes the information shown by the histograms for the two data sets?
Liula [17]

Answer: D

Step-by-step explanation:

Both distributions are symmetric, but oysters tend to have more volume than mussels

7 0
3 years ago
HELP???????????????????????????????????????????????????????? pls? (10 points) (image down below to make it easier to understand.
prisoha [69]

Answer:

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
A bus went halfway from a village to a city at a certain speed. Then it stopped in traffic for an hour. In order to catch up the
k0ka [10]
We have to assume that the speed before being stuck was sufficient to get to the destination on time had there been no delay. Call that speed "s" in km/h.

Since 200 km is "halfway", the total distance must be 400 km.

time = distance / speed
total time = (time for first half) + (delay) + (time for second half)

400/s = 200/s + 1 + 200/(s+10) . . . .times are in hours, distances in km
200/s = 1 + 200/(s+10) . . . . . . . . . . subtract 200/s
200(s+10) = s(s+10) +200s . . . . . . .multiply by s(s+10)
0 = s² +10s - 2000 . . . . . . . . . . . . . .subtract the left side
(s+50)(s-40) = 0
Solutions are s = -50, s = 40

The speed of the bus before the traffic holdup was 40 km/h.
4 0
3 years ago
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