Mr. Rosart selects two students from his class to present their book reports. He places the names of each student in a box and r
2 answers:
Answer:
D. 56%
Step-by-step explanation:
For the fractions we will do:
It depends on if he puts the first name back in, but I am going to asume Mr. Rosart does not, <em>so we will subtract one from the boys for the second pull</em>.
[Wanted over possible]
[Dividing] 14 / 25 = 0.56
[Making a percent] .56 * 100 = 56%
<u />
Have a nice day!
I hope this is what you are looking for, but if not - comment! I will edit and update my answer accordingly. (ノ^∇^)
- Heather
You might be interested in
Answer:
81 cubic foot
Step-by-step explanation:
It is given that the box is packed with cubes whose side is 1 foot. So the volume of one cube is 1 cubic foot.
Now from the figure, we can see that :
Number of cubes fitting the box across its length = 9 cubes
Number of cubes fitting the box across its width = 3 cubes
Number of cubes fitting the box across its height = 3 cubes
And each of these cubes measures 1 x 1 x 1 cubic foot
So the volume of the box can be found out by:
Volume = length x width x height
= 9 x 3 x 3
= 81 cubic foot
Therefore volume of the box is 81 cubic foot.
1. B and Y are 2 events,and Y has already occurred.
2. P(B|Y)=P(B∩Y)/P(Y),
gives the probability of B to occur, once Y has already happened.
3. According to the givens (check the diagram at the bottom, of the described problem),
P(B∩Y)=n(B∩Y)/n(U)=8/26=4/13
P(Y)=n(Y)/n(U)=12/26=6/13
P(B|Y)=P(B∩Y)/P(Y)=(4/13)/(6/13)=4/6=2/3=0.67
2. P(B|Y)=P(B∩Y)/P(Y),
gives the probability of B to occur, once Y has already happened.
3. According to the givens (check the diagram at the bottom, of the described problem),
P(B∩Y)=n(B∩Y)/n(U)=8/26=4/13
P(Y)=n(Y)/n(U)=12/26=6/13
P(B|Y)=P(B∩Y)/P(Y)=(4/13)/(6/13)=4/6=2/3=0.67