Question

Mr. Rosart selects two students from his class to present their book reports. He places the names of each student in a box and randomly picks one at a time. The class has 15 boys and 11 girls. What is the probability that the second name Mr. Rosart picks is a boy, if the first one is a boy also? Round your answer to the nearest percent.
A. 54%
B. 44%
C. 60%
D. 56%

Answer 1

Answer:

D. 56%

Step-by-step explanation:

For the fractions we will do:

$\frac{wanted.outcome}{possible.outcomes}$

      It depends on if he puts the first name back in, but I am going to asume Mr. Rosart does not, so we will subtract one from the boys for the second pull.

[Wanted over possible] $\frac{14}{25}$

[Dividing] 14 / 25 = 0.56

[Making a percent] .56 * 100 = 56%

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Have a nice day!

     I hope this is what you are looking for, but if not - comment! I will edit and update my answer accordingly. (ノ^∇^)

- Heather

Answer 2

D because you need to divide and make the quotient into a percent