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2 years ago

Drag the phases into the box to match the expression

Mathematics

1 answer:

Annette [7]2 years ago

4 0

1- one half more than three fourths of a number
2- three fourths minus one half of a number
3- three fourths minus the sum of a number and one half
HOPE THIS HELPS!!

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Find the distance between two points (-8, 4) and (9, 8)

RoseWind [281]

Answer:

Length between two points:

${ \bf{length = \sqrt{ {9}^{2} - {( - 8)}^{2} + {8}^{2} - {4}^{2} } }} \\ = \sqrt{65}$

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2 years ago

What is the slope of the line shown below?

Brrunno [24]

The slope is D) 4/11.

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3 years ago

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Eric and Mark were at a ball game and visited the concession stand. They each got a hamburger, and Mark got a lemonade and some

LenaWriter [7]

Write an out an equation using the information given. So:

8 + 5 + x - 2 = 14.5
13 + x - 2 = 14.5 
11 + x = 14.5 
x = 3.50

This means that the answer is D.

Hope this helped :)

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3 years ago

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Q3. Find the x and y intercept of the graph of -x + 3y = 19?

Bad White [126]

Answer:

x intercepts (-19,0)

y intercepts (0,19/3)

Step-by-step explanation:

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2 years ago

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The Ace Novelty company produces two souvenirs: Type A and Type B. The number of Type A souvenirs, x, and the number of Type B s

Molodets [167]

Answer:

500 type A; 3500 type B

Step-by-step explanation:

The method of Lagrange multipliers can solve this quickly. For objective function f(x, y) and constraint function g(x, y)=0 we can set the partial derivatives of the Lagrangian to zero to find the values of the variables at the extreme of interest.

These functions are ...

$f(x,y)=4x+2y\\g(x,y)=2x^2+y-4$

The Lagrangian is ...

$\mathcal{L}(x,y,\lambda)=f(x,y)+\lambda g(x,y)\\\\\text{and the partial derivatives are ...}\\\\\dfrac{\partial \mathcal{L}}{\partial x}=\dfrac{\partial f}{\partial x}+\lambda\dfrac{\partial g}{\partial x}=4+\lambda (4x)=0\ \implies\ x=\dfrac{-1}{\lambda}\\\\\dfrac{\partial \mathcal{L}}{\partial y}=\dfrac{\partial f}{\partial y}+\lambda\dfrac{\partial g}{\partial y}=2+\lambda (1)=0\ \implies\ \lambda=-2$

$\dfrac{\partial\mathcal{L}}{\partial\lambda}=\dfrac{\partial f}{\partial\lambda}+\lambda\dfrac{\partial g}{\partial\lambda}=0+2x^2+y-4=0\ \implies\ y=4-2x^2\\\\\text{We know $\lambda$, so we can find x and y:}\\\\x=\dfrac{-1}{-2}=0.5\\\\y=4-2\cdot 0.5^2=3.5$

Since x and y are in thousands, maximum profit is to be had when the company produces ...

500 Type A souvenirs, and 3500 Type B souvenirs

3 0

3 years ago