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3 years ago

Find the area of the circle in terms of Pi. (TT) 10 cm A

Mathematics

1 answer:

Alinara [238K]3 years ago

7 0

Answer:

A≈314.16

Step-by-step explanation:

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Plase help me it would mean a lot

IRINA_888 [86]

Answer:

Drink A

Step-by-step explanation:

Let's find the amount of sugar in each drink in every 35 ounces. (since 35 is the lowest common multiple of 5 and 7)

Drink A

5 fluid ounces --- 11g of sugar

35 fluid ounces --- 11 ×7= 77g of sugar

Drink B

7 fluid ounces --- 10g of sugar

35 fluid ounces --- 10 ×5= 50g of sugar

Since drink A has more sugar in every 35 ounces than drink B, drink A is sweeter.

6 0

3 years ago

Two angles are supplementary if the sum of their measure is 180 degrees. If one of the two supplementary angles measures 85 degr

ale4655 [162]

Answer:

95 degrees.

Step-by-step explanation:

Their sum is 180. You will subtract 85 to get the other half of the whole.

180 - 85 = 95

The other angle is 95 degrees.

4 0

3 years ago

Please answer ASAP! Photo below!

Maru [420]

B

-2 1/4 = -9/4
(-9/4)/(-2/3)

7 0

4 years ago

Read 2 more answers

Which equation can be used to solve for x in the following diagram.

Leokris [45]

I don’t see an attachment for a diagram

6 0

3 years ago

) Set up a double integral for calculating the flux of F=3xi+yj+zk through the part of the surface z=−5x−2y+2 above the triangle

Fynjy0 [20]

The surface (call it $S$ ) is a triangle with vertices at the points

$x=0,y=0\implies z=2\implies(0,0,2)$

$x=0,y=2\implies z=-2\implies(0,2,-2)$

$x=2,y=0\implies z=-8\implies(2,0,-8)$

Parameterize $S$ by

$\vec s(u,v)=(1-v)(2,0,-8)+v\bigg((1-u)(0,2,-2)+u(0,0,2)\bigg)=(2-2v,2v-2uv,-8+6v+4uv)$

with $0\le u\le1$ and $0\le v\le1$ . Take the normal vector to $S$ to be

$\vec s_v\times\vec s_u=(20v,8v,4v)$

Then the flux of $\vec F$ across $S$ is

$\displaystyle\iint_S\vec F(x,y,z)\cdot\mathrm d\vec S=\int_0^1\int_0^1\vec F(x(u,v),y(u,v),z(u,v))\cdot(\vec s_v\times\vec s_u)\,\mathrm du\,\mathrm dv$

$=\displaystyle\int_0^1\int_0^1(6-6v,2v-2uv,-8+6v+4uv)\cdot(20v,8v,4v)\,\mathrm du\,\mathrm dv$

$=\displaystyle8\int_0^1\int_0^1(11v-10v^2)\,\mathrm du\,\mathrm dv=\boxed{\frac{52}3}$

8 0

4 years ago