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alexira [117]
3 years ago
8

Operations with Fractions

Mathematics
2 answers:
Mila [183]3 years ago
6 0

Answer:

option a or c

Step-by-step explanation:

hope it helps u

kumpel [21]3 years ago
5 0

Answer:

answer is A

Step-by-step explanation:

if you minus them the in the calculator you get the first answer!

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❗️❗️❗️Find the length of side x in simplest radical form with a rational denominator.❗️❗️❗️
tiny-mole [99]

Answer:

x=\frac{\sqrt{14} }{2}

Step-by-step explanation:

Notice that you are given an isosceles right-angle triangle to solve, since each of its two acute angles measures 45^o. Then such means that the sides opposite to these acute angles (the so called "legs" of this right angle triangle) must also be of the same length (x).

We can then use the Pythagorean theorem that relates the square of the hypotenuse to the addition of the squares of the triangles legs:

(\sqrt{7})^2=x^2+x^2\\7=2\,x^2\\x^2=\frac{7}{2} \\x=+/-\sqrt{\frac{7}{2}} \\x=+/-\frac{\sqrt{14} }{2}

We use just the positive root, since we are looking for an actual length. then, the requested side is:

x=\frac{\sqrt{14} }{2}

6 0
3 years ago
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riadik2000 [5.3K]
1.-4
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here you go.
5 0
2 years ago
X^2+25<br><br> A.(x+5)(x+5)<br> B.(x+5)(x-5)<br> C.(x-5)(x/5)<br> D.prime
adell [148]
It’s prime because none of the other answers work.
8 0
3 years ago
The half life of silicone-32 is 710 years. If 30 grams is present now, how much will be present in 300 years?
Irina18 [472]

Answer:

22.38 g of silicone-32 will be present in 300 years.

Step-by-step explanation:

A radioactive half-life refers to the amount of time it takes for half of the original isotope to decay and its given by

                                           N(t)=N_0(\frac{1}{2})^{\frac{t}{t_{1/2}}

where,

N(t) = quantity of the substance remaining

N_0 = initial quantity of the substance

t = time elapsed

t_{1/2} = half life of the substance

From the information given we know:

  • The initial quantity of silicone-32 is 30 g.
  • The time elapsed is 300 years.
  • The half life of silicone-32 is 710 years.

So, to find the quantity of silicone-32 remaining we apply the above equation

N(t)=30\left(\frac{1}{2}\right)^{\frac{300}{710}}=30\left(\frac{1}{2}\right)^{\frac{30}{71}}\approx22.38 \:g

22.38 g of silicone-32 will be present in 300 years.

7 0
3 years ago
Quadratic inequalities
lina2011 [118]
See picture for rough graph

7 0
3 years ago
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