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schepotkina [342]
3 years ago
10

Equation 13.00 x 0.53

Mathematics
2 answers:
Serga [27]3 years ago
3 0
The answer is 6.89 because calculators
Bezzdna [24]3 years ago
3 0
The answer is 6.89. Just multiply them together.
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The equation of a circle is x2 + y2 + Cx + Dy + E = 0. If the radius of the circle is decreased without changing the coordinates
valkas [14]

Answer:

Option E

Step-by-step explanation:

The standard equation of circle is:- (x-h)² + (y-k)² = r²

where (h,k) is center point and r is radius

If radius r is decreased then also (h,k) remains same, only r² increases

Equation given in question is x² + y² + Cx + Dx + E=0

So, C and D will remain same but E will increase

4 0
3 years ago
The ideal width of a certain conveyor belt for a manufacturing plant is 50 in. Conveyor belts can vary from the ideal width by a
sdas [7]
Thank you for posting your question here at brainly. I hope the answer will help you. Feel free to ask more questions.

If the ideal is 50 and the max variation is 7/32in, then that's 7/32 under 50 and 7/32 over 50. 
<span>So, 50-7/32= 49 25/32, and 50+7/32 = 50 7/32. </span>
<span>So the acceptable width is 49 25/32 to 50 7/32.</span>

5 0
3 years ago
Read 2 more answers
Have students write the answer to the essential question and draw examples to explain their answer.
hram777 [196]

What is the essential question? We need more details please :)

7 0
3 years ago
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Combine like terms to create an equivalent expression. Enter any coefficients as simplified proper or improper fractions or inte
Sonja [21]

Answer:

  1 -9/7n

Step-by-step explanation:

  \dfrac{1}{7}-3\left(\dfrac{3}{7}n-\dfrac{2}{7}\right)=\dfrac{1}{7}-\dfrac{3\cdot3}{7}n+\dfrac{3\cdot2}{7}=\dfrac{1}{7}+\dfrac{6}{7}-\dfrac{9}{7}n\\\\=\dfrac{1+6}{7}-\dfrac{9}{7}n=\boxed{1-\dfrac{9}{7}n}

5 0
2 years ago
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A spring stretches out by 8cm when a 0.2 kg weight is placed on it. How much does the spring stretch by when a 0.5 kg weight is
Ierofanga [76]

m₁ = mass hanged initially = 0.2 kg

x₁ = initial stretch in the spring = 8 cm = 0.08 m

k = spring constant of the spring

the weight of the mass hanged is balanced by the spring force by the spring hence

Spring force = weight of mass hanged

k x₁ = m₁ g

k (0.08) = (0.2) (9.8)

k = 24.5 N/m


m₂ = mass hanged later = 0.5 kg

x₂ = final stretch in the spring = ?

k = spring constant of the spring = 24.5 N/m

the weight of the mass hanged is balanced by the spring force by the spring hence

Spring force = weight of mass hanged

k x₂ = m₂ g

(24.5) x₂  = (0.5) (9.8)

x₂  = 0.2 m = 20 cm



5 0
3 years ago
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