The expression given by f(x)=a(x-h)^2+k is a the equation of a vertex where (h,k) is the vertex. The importance of h is that it represents the x-intercept, the lowest or the highest point of the graph of the expression. This is a very important factor when determining the turning points of parabolas
I'm assuming the limit is supposed to be
Multiply the numerator by its conjugate, and do the same with the denominator:
so that in the limit, we have
Factorize the first term in the denominator as
The 
terms cancel, leaving you with
and the limand is continuous at 
, so we can substitute it to find the limit has a value of -1/18.
Answer:
yes
Step-by-step explanation:
IM new plz add me brainless did the math
Nope because she only used two of the net faces
Answer:
m = 2
n = 4
Step-by-step explanation:
Ok so to solve this, you want to get it so there is only one variable and then solve that equation. To do this, you can start by doing:
3m + n = 10
multiply both sides by 2
6m + 2n = 20
now, in both of your equations you have 2n so you can add the two equations:
6m + 2n = 20
+ 5m - 2n = 2
11m = 22
divide both sides by 11
m = 2.
Now, plug this value into the original equation, 3m + n = 10:
3 * 2 + n = 10
6 + n = 10
subtract 6 from both sides
n = 4
