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2 years ago

10

Nia puts $750 into a savings account. The simple interest rate for the savings account is 3%. If Nia does not withdraw or deposi

t any additional money, how much money will be in Nia’s account at the end of 2.5 years?

1 answer:

7nadin3 [17]2 years ago

3 0

Answer:

63%

Step-by-step explanation:

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A parabola intersects the x-axis at x = 3 and x = 9.

Novay_Z [31]

Answer:

6

Step-by-step explanation:

This function corresponds to 'even' function, then

in order to calculate the 'x' of the vertex: (3+9)/2=6.

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3 years ago

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Write a linear equation that passes the point (2,-9) and has a slope of -5

Nezavi [6.7K]

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idk sorry

Step-by-step explanation:

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3 years ago

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Geometry Helps please<br> (Only correct Answers only please) Thank you very much.

Levart [38]

<h3>Exact Answer: (160/3)pi</h3><h3>Approximate Answer: 167.47</h3>

The approximate answer results when you use pi = 3.14, and this approximate answer is rounded to two decimal places

note that (160/3)pi is the same as 160pi/3

========================================================

Work Shown:

r = radius = 4

h = height = 10

V = volume of cone

V = (1/3)pi*r^2*h

V = (1/3)pi*4^2*10

V = (160/3)pi exact answer

V = (160/3)*3.14

V = 167.46666....

V = 167.47 approximate answer rounded to two decimal places

8 0

3 years ago

A particle is moving along the x-axis so that its position at t ≥ 0 is given by s(t)=(t)ln(5t). Find the acceleration of the par

lyudmila [28]

Answer:

$a(\frac{1}{5e})=5e$

Step-by-step explanation:

we are given equation for position function as

$s(t)=tln(5t)$

Since, we have to find acceleration

For finding acceleration , we will find second derivative

$s'(t)=\frac{d}{dt}\left(t\ln \left(5t\right)\right)$

$=\frac{d}{dt}\left(t\right)\ln \left(5t\right)+\frac{d}{dt}\left(\ln \left(5t\right)\right)t$

$=1\cdot \ln \left(5t\right)+\frac{1}{t}t$

$s'(t)=\ln \left(5t\right)+1$

now, we can find derivative again

$s''(t)=\frac{d}{dt}\left(\ln \left(5t\right)+1\right)$

$=\frac{d}{dt}\left(\ln \left(5t\right)\right)+\frac{d}{dt}\left(1\right)$

$=\frac{1}{t}+0$

$a(t)=\frac{1}{t}$

Firstly, we will set velocity =0

and then we can solve for t

$v(t)=s'(t)=\ln \left(5t\right)+1=0$

we get

$t=\frac{1}{5e}$

now, we can plug that into acceleration

and we get

$a(\frac{1}{5e})=\frac{1}{\frac{1}{5e}}$

$a(\frac{1}{5e})=5e$

5 0

3 years ago

At a baseball game, a vender sold a combined total of 236 sodas and hot dogs. The number of hot dogs sold was 50 less than the n

ELEN [110]

143 and 93

143 sodas 93 dogs

7 0

3 years ago