The way you should go about solving this really depends on how your teacher taught you...However, here's what I would recommend...
You know that 1/2 an hour is equal to 30 minutes, and 3/4 of an hour is equal to 45 minutes.
Using this you can then solve for how many pages she read per minute by dividing the number of pages read by the number of minutes read:11 pages/ 30 minutes to give you Monday's reading speed,and18 pages/ 45 minutes to give you Tuesday's reading speed.
Next, to calculate a percentage increase you need to do the following:
1. Determine the difference between the speeds (this means you will subtract Monday's reading speed from Tuesday's reading speed.)
2. Next you take that number and divide it by Monday's reading speed.
3. Multiply that answer by 100 to get the percentage.
I'm not going to tell you the speeds, as you should try to attempt to solve it by yourself, and I'm sure you need to show your work. I will however tell you that you should find there was a 3.3% increase from Monday to Tuesday.
If you need more help, let me know!
Answer:
23 over 15 or 1.533
Step-by-step explanation:
Group like terms:
1+(3/5+-1/15)
Find LCD:
1+9/15+-1/15
Combine numerators:
15/15+8/15
And you get 23/15
Simplified:1 8/15
Decimal: 1.533
Answer:
And if we solve for a we got
Step-by-step explanation:
Previous concepts
Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".
The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".
Solution to the problem
Let X the random variable that represent the hourly rates of a population, and for this case we know the distribution for X is given by:
For this part we want to find a value a, such that we satisfy this condition:
(a)
(b)
Both conditions are equivalent on this case. We can use the z score again in order to find the value a.
As we can see on the figure attached the z value that satisfy the condition with 0.80 of the area on the left and 0.20 of the area on the right it's z=0.842. On this case P(Z<0.842)=0.8 and P(z>0.842)=0.20
If we use condition (b) from previous we have this:
But we know which value of z satisfy the previous equation so then we can do this:
And if we solve for a we got