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3 years ago

What is the solution of the system?

Mathematics

2 answers:

barxatty [35]3 years ago

7 0

The correct answer is A.

Greeley [361]3 years ago

3 0

Answer:

there is no solution

Step-by-step explanation:

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You are spreading fertilizer on a golf course at the rate of 40 pounds per 10,000 square feet. If the course is 320 acres, how m

NemiM [27]

1 Acre = 43560 square feet
1 Ton = 2000 pounds

320 Acres = 320 * 43560 square feet = 13939200 = 1393.92 * 10,000

1393.92 *40 pounds needed = 55756.8
55756.8 / 2000= 27.8784

5 0

3 years ago

Read 2 more answers

If cos⁡ x=−45, and 180° < x < 270°, what is tan⁡(2x)?

iVinArrow [24]

$Tan2x =\frac{-24}{7}$

Step-by-step explanation:

Here we have , cos x = -4/5 ( corrected as given -45 which is not possible ) ,

180° < x < 270° i.e. in third quadrant . We need to find tan⁡(2x) . Let's find out:

⇒ $Tan\alpha = \frac{sin\alpha }{cos\alpha }$

⇒ $Tan\alpha = \frac{\sqrt{1-(cos\alpha)^2} }{cos\alpha }$

⇒ $Tan\alpha = \frac{\sqrt{1-(\frac{-4}{5})^2} }{\frac{-4}{5} }$

⇒ $Tan\alpha = \frac{-5}{4}\sqrt{1-(\frac{16}{25}) }$

⇒ $Tan\alpha = \frac{-5}{4}\sqrt{(\frac{25-16}{25}) }$

⇒ $Tan\alpha = \frac{-5}{4}(\frac{3}{5}) }$

⇒ $Tan\alpha = \frac{-3}{4}$ , since in third quadrant . $Tan\alpha = \frac{-3}{4}$ remains same .

Now , $Tan2x = \frac{2tanx}{1-(tanx)^{2}}}$

⇒ $Tan2x = \frac{2tanx}{1-(tanx)^{2}}}$

⇒ $Tan2x = \frac{2(\frac{-3}{4})}{1-(\frac{-3}{4})^{2}}}$

⇒ $Tan2x = \frac{-3}{2}(\frac{16}{7})$

⇒ $Tan2x =\frac{-24}{7}$

Therefore, $Tan2x =\frac{-24}{7}$ .

5 0

4 years ago

Scott is using a 12 foot ramp to help load furniture into the back of a moving truck. if the back of the truck is 3.5 feet from

Over [174]

A 12 feet ramp is used to load stuff into the truck which is at a height of 3.5 feet from ground.

The ramp forms a Right triangle with ground and height of truck.

In the Right triangle, hypotenuse is 12 feet and height is 3.5 feet. We need to find horizontal base of right triangle.

We can use Pythagorean theorem that is given by :-

(Hypotenuse)² = (Base)² + (Height)²

(12)² = (Base)² + (3.5)²

144 = (Base)² + 12.25

(Base)² = 144 - 12.25

(Base)² = 131.75

(Base) = √131.75

$Base = \sqrt{131.75} = 11.48 \; feet$

So, horizontal distance is 11.48 feet.

5 0

4 years ago

The admission fee at an amusement park is $12, and each ride costs $3.50. The park also offers an all-day pass with unlimited ri

gavmur [86]

Solve using system of equations.
y=total money spent, x=amount of rides
y=12+3.5x
y=33
Solve! Set them equal to each other
12+3.5x=33
-12 -12
3.5x=21
x=6
After six rides the all day pass would be cheaper. ;)

6 0

3 years ago

Factor completely 3a4y3 − 12a3y2 + 6a2y.

Firlakuza [10]

Step-by-step explanation:

$3a^4y^3-12a^3y^2+6a^2y=(3a^2y)(a^2y^2)-(3a^2y)(4ay)+(3a^2y)(2)\\\\=(3a^2y)(a^2y^2-4ay+2)$

5 0

3 years ago