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evablogger [386]
2 years ago
14

Solve by completing the square. Show all steps for full credit. X^2-6x+8=0

Mathematics
1 answer:
Kruka [31]2 years ago
5 0

answer:

x = 2 \ , \ 4

step-by-step explanation:

\sf x^2-6x+8=0

\sf x^2-4x-2x+8=0

\sf x(x-4)-2(x-4)=0

\sf (x-4)(x-2) = 0

\sf x = 2 \ , \ 4

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3 years ago
Finding the Midpoint of the Two Coordinates<br> 6.) A(-2, 3), B(5,-1)
RoseWind [281]

Answer:

The answer is

<h2>( \frac{3}{2}  \: , \: 1) \\</h2>

Step-by-step explanation:

The midpoint M of two endpoints of a line segment can be found by using the formula

M = (  \frac{x1 + x2}{2} , \:  \frac{y1 + y2}{2} )\\

From the question the points are

A(-2, 3), B(5,-1)

The midpoint is

M = ( \frac{ - 2 + 5}{2} \:   , \:  \frac{3 - 1}{2} ) \\   = ( \frac{3}{2}  \: , \:  \frac{2}{2} )

We have the final answer as

( \frac{3}{2}  \: , \: 1) \\

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