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atroni [7]
3 years ago
12

What are the Variable Terms, Coefficients, and Constants for 8r + 7 - 2r

Mathematics
1 answer:
Sav [38]3 years ago
4 0
Variable: r constant: 7 coefficient: -2 and 8
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An rock is thrown upward from a platform that is 188 feet above ground at 80 feet per second. Use the projectile formula to dete
serious [3.7K]

Answer:

6.74 s

Step-by-step explanation:

y = ½ at² + vt + h

Given a = -32, v = 80, h = 188:

y = ½ (-32) t² + (80) t + (188)

y = -16t² + 80t + 188

When y = 0:

0 = -16t² + 80t + 188

0 = 4t² − 20t − 47

Solve with quadratic formula:

t = [ -(-20) ± √((-20)² − 4(4)(-47)) ] / 2(4)

t = [ 20 ± √(400 + 752) ] / 8

t = (20 ± √1152) / 8

t > 0, so:

t = (20 + √1152) / 8

t ≈ 6.74

8 0
3 years ago
If g(x) = 2(x − 4), find the value of x if g(x) = 20. 32 12
nlexa [21]

Answer:

The value of x is 14

Step-by-step explanation:

we have

g(x)=2(x-4) ------> equation A

In this problem we have

g(x)=20

Substitute the value of g(x) in the equation A and solve for x

20=2(x-4)

Divide by 2 both sides

20/2=2(x-4)/2

10=(x-4)

Adds 4 both sides

10+4=(x-4)+4

x=14

6 0
3 years ago
Read 2 more answers
Pleasee help, thank you so much
dezoksy [38]

Answer:

-2

Step-by-step explanation:

Use the slope formula when given two points

Slope formula = \frac{y_2-y_1}{x_2-x_1}

( the x and y values are determined by the given points )

Given the points ( 0 , 5 ) and ( 1 , 3 )

Plug in the x and y values of the given points into the formula

( remember y values on top x values on bottom )

slope=\frac{5-3}{0-1} \\5-3=2\\0-1=-1\\slope=\frac{2}{-1} =-2

Hence, the answer is D

5 0
3 years ago
ANSWER ASAP RIGHT ANSWER = BRAINLIST 100 POINTS
ale4655 [162]

Answer:

-6.75

Hooe it helps!

Please mark brainliest

8 0
3 years ago
Read 2 more answers
What is the derivative of y with respect to x if y = 2/X4
zepelin [54]
You're correct, the answer is C.

Given any function of the form y=x^n, then the derivative of y with respect to x (\frac{dy}{dx}) is written as:
\frac{dy}{dx}=nx^n^-^1

In which n is any constant, this is called the power rule for differentiation.

For this example we have y= \frac{2}{x^4}, first lets get rid of the quotient and write the expression in the form y=x^n:
y= \frac{2}{x^4} =2x^-^4

Now we can directly apply the rule stated at the beginning (in which n=-4):
\frac{dy}{dx}=(2)(-4)x^{-4-1}=-8 x^{-5}= -\frac{8}{x^5}

Note that whenever we differentiate a function, we simply "ignore" the constants (we take them out of the derivative).
6 0
3 years ago
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