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3 years ago

Can someone show the work for GCF for 130 and 104?

Mathematics

2 answers:

USPshnik [31]3 years ago

7 0

Answer:

Step-by-step explanation:

To get the Greates Common Factor (GCF) of 130 and 104 we need to factor each value first and then we choose all the copies of factors and multiply them:

130: 2 13

104: 2 13

GCF: 2 13

The Gratest Common Factor (GCF) is: 2 x 13 = 26

sleet_krkn [62]3 years ago

4 0

The answer is GCF=26

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If r = 8 units and h = 10 units, what is the volume of the cylinder shown above? use 3.14 for pi,

Basile [38]

I hope this helps you

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Volume =3,14.8^2.10

Volume =31,4.64

Volume =200,96

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3 years ago

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kaheart [24]

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3 years ago

Expand the binomial (2x+5)^5

Whitepunk [10]

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4 years ago

<img src="https://tex.z-dn.net/?f=%5Csf%202x%2B7%2B8x%3D35" id="TexFormula1" title="\sf 2x+7+8x=35" alt="\sf 2x+7+8x=35" align="

Dafna11 [192]

Answer:

x=14/5

Step-by-step explanation:

Group like terms

2x+8x+7=35

Add similar elements: 2x+8x=10x

10x+7=35

Subtract 7 from both sides:

10x+7−7=35−7

Simplify

10x=28

Divide both sides by 10

10x/10 =28/10

Simplify:

x=14/5

7 0

3 years ago

Examine the system of equations.

MrMuchimi

answer:

$x = - 2 \\ y = 2 \\ \\ ( - 2, \: 2)$

explanation:

$y = - \frac{1}{2} x + 1 \\ y = 2x + 6 \\ first \: equation \: add \: \frac{1}{2} from \: both \\ sides \\ \\ second \: equation \: subtract \: 2x \: from \\ both \: sides \\ \\ y + \frac{1}{2} x = 1 \\ y - 2x = 6 \\ solve \: the \: first \: equation \\ \\ y + \frac{1}{2} x = 1 \\ subtract \: \frac{x}{2} from \: both \: sides \\ \\ y = - \frac{1}{2} x + 1 \\ substitute \: - \frac{x}{2} + 1 \: for \: y \: in \: the \\ other \: equation \\ \\ - \frac{1}{2} x + 1 - 2x = 6 \\ add \: \frac{1}{2} x \: to \: 2x \\ \\ - \frac{5}{2} x + 1 = 6 \\ subtract \: 1 \: from \: both \: sides \\ \\ - \frac{5}{2} x = 5 \\ divide \: both \: sides \: by \: - \frac{5}{2} \\ \\ x = - 2 \\ substitute \: the \: value \: of \: x \: into \\ an \: equation \\ \\ y = - \frac{1}{2} ( - 2) + 1 \\ distribute \\ \\ y = 1 + 1 \\ add \\ \\ y = 2 \\ \\ ( - 2, \: 2)$

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3 years ago