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3 years ago

Can someone show the work for GCF for 130 and 104?

Mathematics

2 answers:

USPshnik [31]3 years ago

7 0

Answer:

Step-by-step explanation:

To get the Greates Common Factor (GCF) of 130 and 104 we need to factor each value first and then we choose all the copies of factors and multiply them:

130: 2 13

104: 2 13

GCF: 2 13

The Gratest Common Factor (GCF) is: 2 x 13 = 26

sleet_krkn [62]3 years ago

4 0

The answer is GCF=26

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Dante bought a new graduated cylinder for his chemistry class. It holds 847 milliliters of liquid. If the cylinder has a radius

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Answer:

Option a) $h=28\ cm$

Step-by-step explanation:

we know that

The volume of a cylinder is equal to

$V=\pi r^{2}h$

we have

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$847\pi\ ml=847\pi\ cm^{3}$

$r=5.5\ cm$

substitute in the formula and solve for h

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4 years ago

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ArbitrLikvidat [17]

Answer:

$\sum x= 37, \sum y= 672, \sum xy =2907, \sum x^2 =173, \sum y^2 = 51320$

Where:

$S_{xy}=\sum_{i=1}^n x_i y_i -\frac{(\sum_{i=1}^n x_i)(\sum_{i=1}^n y_i)}{n}$

$S_{xx}=\sum_{i=1}^n x^2_i -\frac{(\sum_{i=1}^n x_i)^2}{n}$

With these we can find the sums:

$S_{xx}=\sum_{i=1}^n x^2_i -\frac{(\sum_{i=1}^n x_i)^2}{n}=173-\frac{37^2}{9}=20.889$

$S_{xy}=\sum_{i=1}^n x_i y_i -\frac{(\sum_{i=1}^n x_i)(\sum_{i=1}^n y_i){n}}=2907-\frac{37*672}{9}=144.333$

And the slope would be:

$m=\frac{144.333}{20.889}=6.90953$

Nowe we can find the means for x and y like this:

$\bar x= \frac{\sum x_i}{n}=\frac{37}{9}=4.111$

$\bar y= \frac{\sum y_i}{n}=\frac{672}{9}=74.667$

And we can find the intercept using this:

$b=\bar y -m \bar x=74.667-(6.9096*4.111)=46.241$

So the line would be given by:

$y=6.9096 x +46.241$

And for this case the value of the slope m = 6.9096 means that for every increase of 1 unit in the number of years we have an increase of approximately 6.9096 in the grades of the test.

Step-by-step explanation:

Data given:

x: 3, 4, 4, 5, 3, 6, 2, 7, 3

y: 61, 68, 75, 82, 73, 90, 58, 93, 72

$m=\frac{S_{xy}}{S_{xx}}$

$\sum x= 37, \sum y= 672, \sum xy =2907, \sum x^2 =173, \sum y^2 = 51320$

Where:

$S_{xy}=\sum_{i=1}^n x_i y_i -\frac{(\sum_{i=1}^n x_i)(\sum_{i=1}^n y_i)}{n}$

$S_{xx}=\sum_{i=1}^n x^2_i -\frac{(\sum_{i=1}^n x_i)^2}{n}$

With these we can find the sums:

$S_{xx}=\sum_{i=1}^n x^2_i -\frac{(\sum_{i=1}^n x_i)^2}{n}=173-\frac{37^2}{9}=20.889$

$S_{xy}=\sum_{i=1}^n x_i y_i -\frac{(\sum_{i=1}^n x_i)(\sum_{i=1}^n y_i){n}}=2907-\frac{37*672}{9}=144.333$

And the slope would be:

$m=\frac{144.333}{20.889}=6.90953$

Nowe we can find the means for x and y like this:

$\bar x= \frac{\sum x_i}{n}=\frac{37}{9}=4.111$

$\bar y= \frac{\sum y_i}{n}=\frac{672}{9}=74.667$

And we can find the intercept using this:

$b=\bar y -m \bar x=74.667-(6.9096*4.111)=46.241$

So the line would be given by:

$y=6.9096 x +46.241$

And for this case the value of the slope m = 6.9096 means that for every increase of 1 unit in the number of years we have an increase of approximately 6.9096 in the grades of the test.

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