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Evgen [1.6K]
2 years ago
15

Which of the following graphs show a proportional relationship?choose all that apply​

Mathematics
2 answers:
ziro4ka [17]2 years ago
5 0

Answer:

A

Step-by-step explanation:

Mrac [35]2 years ago
4 0

Answer:

the first one coz the all the cordinates of the graph have the same number on both axis' we can take example of 2,2 3,3 5.5,5.5 etc.

whereas the other graph starts itself on the why axis instead at the origin.

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Please answer please please thank you
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Evaluate the expression under the given conditions. tan(2); cos() = 5 13 , in quadrant i
Nataliya [291]

The solution to given expression tan(2θ) is 22.615°

For given question,

We have been given an expression tan(2θ)

Given that cos(θ) = 5/13, and θ is in quadrant 1.

We know that the trigonometric identity

sin²θ + cos²θ = 1

⇒ cos²θ = (5/13)²

⇒ sin²θ = 1 - 25/169

⇒ sin²θ = 169 - (25/169)

⇒ sin²θ = 144/169

⇒ sin(θ) = 12/13

We know that the identity cos(2x) = cos²x - sin²x

⇒ cos(2θ) = cos²θ - sin²θ

⇒ cos(2θ) = 25/169 - 144/169

⇒ cos(2θ) = -119/169

And sin(2x) = 2sin(x)cos(x)

⇒ sin(2θ) = 2sin(θ)cos(θ)

⇒ sin(2θ) = 2 × 12/13 × 5/13

⇒ sin(2θ) = 120/169

We know that, tan(x) = sin(x)/cos(x)

⇒ tan(2θ) = sin(2θ)/cos(2θ)

⇒ tan(2θ) = (120/169) / (-119/169)

⇒ tan(2θ) = 120 / (-119)

⇒ tan(2θ) = -1.008

Since θ is in quadrant 1, tan(2θ) = 1.008

⇒ 2θ = arctan(1.008)

⇒ 2θ = 45.23

⇒ θ = 22.615°

Therefore, the solution to given expression tan(2θ) is 22.615°

Learn more about the expression here:

brainly.com/question/14961928

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2 years ago
Find the sum of the arithmetic sequence. -1, 2, 5, 8, 11, 14, 17
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Step-by-step explanation:

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Which of the following represents the coordinates of point A?
KiRa [710]
The coordinates of A will be (2P +M)/3
= (2(16, 14) +(1, 4))/3 = (33/3, 32/3) = (11, 32/3)

The appropriate choice is
  (C) (11, 32/3)

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You will note that the coordinates of A are the weighted average of the coordinates of the end points. The weighting is the reverse of the ratio of the line segments. That is, the point adjacent to the shortest segment gets the highest weighting. (This is typical of the solution to "mixture" problems.)
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