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abruzzese [7]
2 years ago
7

This for whoever wants to get 15 points for free.......Your welcome

Mathematics
2 answers:
liraira [26]2 years ago
8 0

Answer:

kk

Step-by-step explanation:

Kobotan [32]2 years ago
7 0

Answer:THANK YOUUUUUUU

Step-by-step explanation:

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Find the probability of selecting none of the correct six integers in a lottery, where the order in which these integers are sel
Andre45 [30]

Answer:

Step-by-step explanation:

Given

there are six integers to win a lottery

case-1 Integer not exceeding 40

no of ways to choose 6 incorrect numbers

=\dfrac{^{34}C_{6}}{^{40}C_{6}}

=0.35

Case-2 no of ways to choose 6 incorrect numbers out of 48 integers

=\dfrac{^{42}C_{6}}{^{48}C_{6}}

=0.427

Case-3 no of ways to choose 6 incorrect numbers out of 56 integers

\dfrac{^{50}C_{6}}{^{56}C_{6}}

=0.489

Cae-4 no of ways to choose 6 incorrect numbers out of 64 integers

\dfrac{^{58}C_{6}}{^{64}C_{6}}

=0.54

6 0
3 years ago
Find the distance between the following coordinates: I(-a,b), J(a,b)
olchik [2.2K]

Answer:

2a

Step-by-step explanation:

using distance formula:

√(x₂-x₁)² + (y₂-y₁)²

putting values,

√{a-(a)}² + {b-b}² = √ {a+a}² + 0²

= √(2a)² = √4a² = 2a

Hope this helps:)

8 0
3 years ago
If r = 32 and t = 8, what is the value of the following expression?
tatiyna
C. 44 you need to do pendas
5 0
3 years ago
A realtor listed a house that was 45 yards by 10 yards..What is the total square footage of the house
Alex17521 [72]
4050 ft is the total square footage of the house.
6 0
3 years ago
Find an equation for the plane that is tangent to the surface z equals ln (x plus y )at the point Upper P (1 comma 0 comma 0 ).
alexira [117]

Let f(x,y,z)=z-\ln(x+y). The gradient of f at the point (1, 0, 0) is the normal vector to the surface, which is also orthogonal to the tangent plane at this point.

So the tangent plane has equation

\nabla f(1,0,0)\cdot(x-1,y,z)=0

Compute the gradient:

\nabla f(x,y,z)=\left(\dfrac{\partial f}{\partial x},\dfrac{\partial f}{\partial y},\dfrac{\partial f}{\partial z}\right)=\left(-\dfrac1{x+y},-\dfrac1{x+y},1\right)

Evaluate the gradient at the given point:

\nabla f(1,0,0)=(-1,-1,1)

Then the equation of the tangent plane is

(-1,-1,1)\cdot(x-1,y,z)=0\implies-(x-1)-y+z=0\implies\boxed{z=x+y-1}

7 0
3 years ago
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