All categories

3 years ago

HELP ME WITH MY MATH

Mathematics

2 answers:

iogann1982 [59]3 years ago

8 0

36. Correct me if I’m wrong!

PtichkaEL [24]3 years ago

7 0

Answer:36

Step-by-step explanation:

You might be interested in

A functionf(x) is graphed on the coordinate plane.

ollegr [7]

Answer:

y = -1/2x +1

Step-by-step explanation:

The y intercept is 1 (this is where it crosses the y intercept)

(0,1) and (2,0) are two points on the line

The slope is given by

m = (y2-y1)/(x2-x1)

= (0-1)/(2-0)

= -1/2

The slope is -1/2

The slope intercept form is y = mx+b where m is the slope and b is the y intercept

y = -1/2x +1

8 0

3 years ago

Read 2 more answers

Make cos C the subject of the formula<br> C?= a? + b? - 2ab cos C

lara31 [8.8K]

<h3>Answer: Choice E</h3>

Work Shown:

$c^2 = a^2 + b^2 - 2ab\cos(C)\\\\c^2 + 2ab\cos(C) = a^2 + b^2\\\\2ab\cos(C) = a^2 + b^2 - c^2\\\\\boldsymbol{\cos(C) = \frac{a^2 + b^2 - c^2}{2ab}}\\\\$

5 0

2 years ago

Identify whether each phrase is an expression, equation, or inequality.

OverLord2011 [107]

Answer:

swich the one attached to equation with the one attached to expression

Step-by-step explanation:

an equation need to have an equals sign, an expression doesnt.

8 0

3 years ago

Read 2 more answers

The probability that two people have the same birthday in a room of 20 people is about 41.1%. It turns out that

salantis [7]

Answer:

a) Let X the random variable of interest, on this case we know that:

$X \sim Binom(n=20, p=0.411)$

This random variable represent that two people have the same birthday in just one classroom

b) We can find first the probability that one or more pairs of people share a birthday in ONE class. And we can do this:

$P(X\geq 1 ) = 1-P(X$

And we can find the individual probability:

$P(X=0) = (20C0) (0.411)^0 (1-0.411)^{20-0}=0.0000253$

And then:

$P(X\geq 1 ) = 1-P(X$

And since we want the probability in the 3 classes we can assume independence and we got:

$P= 0.99997^3 = 0.9992$

So then the probability that one or more pairs of people share a birthday in your three classes is approximately 0.9992

Step-by-step explanation:

Previous concepts

A Bernoulli trial is "a random experiment with exactly two possible outcomes, "success" and "failure", in which the probability of success is the same every time the experiment is conducted". And this experiment is a particular case of the binomial experiment.

The binomial distribution is a "DISCRETE probability distribution that summarizes the probability that a value will take one of two independent values under a given set of parameters. The assumptions for the binomial distribution are that there is only one outcome for each trial, each trial has the same probability of success, and each trial is mutually exclusive, or independent of each other".

The probability mass function for the Binomial distribution is given as:

$P(X)=(nCx)(p)^x (1-p)^{n-x}$

Where (nCx) means combinatory and it's given by this formula:

$nCx=\frac{n!}{(n-x)! x!}$

Solution to the problem

Part a

Let X the random variable of interest, on this case we know that:

$X \sim Binom(n=20, p=0.411)$

This random variable represent that two people have the same birthday in just one classroom

Part b

We can find first the probability that one or more pairs of people share a birthday in ONE class. And we can do this:

$P(X\geq 1 ) = 1-P(X$

And we can find the individual probability:

$P(X=0) = (20C0) (0.411)^0 (1-0.411)^{20-0}=0.0000253$

And then:

$P(X\geq 1 ) = 1-P(X$

And since we want the probability in the 3 classes we can assume independence and we got:

$P= 0.99997^3 = 0.9992$

So then the probability that one or more pairs of people share a birthday in your three classes is approximately 0.9992

4 0

4 years ago

Multiplying desimals

kolezko [41]

Answer:

Line up the numbers on the right - do not align the decimal points.

Starting on the right, multiply each digit in the top number by each digit in the bottom number, just as with whole numbers.

Add the products.

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers