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BlackZzzverrR [31]
3 years ago
13

Answer this ! please

Mathematics
1 answer:
saw5 [17]3 years ago
8 0
The answer is D
2y/y+2 + 4/y+2= 2
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1. find the product and write it in simplest form: 1 1/3 x 3/8 =
I am Lyosha [343]

Answer:

The answer to number 1 is A.

Step-by-step explanation:

To find this answer, I made 1 1/3 into one big fraction. I multiplied the denominator by the whole number (3x1) and then added that product to the numerator. (3+1). The new fraction is now 4/3 (you keep the denominator the same). The next step is to multiply 4/3 by 3/8. When multiplying fractions, you multiply straight across (the numerator by the numerator, and the denominator by the denominator). Your answer is now 12/24. The final step is to simplify the answer. Since 12 is half of 24, the answer is 1/2.

3 0
3 years ago
Solve the system using substitution. 5x-y=73 and 2y=x
galina1969 [7]

Answer:

Point form:( \frac{146}{9} \\\\, \frac{73}{9})

Equation form: x= \frac{146}{9}, y= \frac{73}{9}

Step-by-step explanation:

Plz mark brainliest.

7 0
3 years ago
Given the parallelogram below, find m and n.
Alex73 [517]

9514 1404 393

Answer:

  • m = 5
  • n = 12

Step-by-step explanation:

Opposite sides of a parallelogram are congruent.

  m + 1 = 6

  m = 5

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  n = 12

8 0
3 years ago
A flashlight shines straight up into the sky, 9 ft to the right of a tent located at the origin. For which values of A, B, and C
lina2011 [118]

Answer:

Im not sure but i think its A=1, B=0, and C=9

Step-by-step explanation:

hope this helps

8 0
4 years ago
What is the equation?
Cerrena [4.2K]

to get the equation of a straight line, all we need is two points, hmmm say this line runs over (0 , -2) and (3 , 0), so let's use those.

\bf (\stackrel{x_1}{3}~,~\stackrel{y_1}{0})\qquad (\stackrel{x_2}{0}~,~\stackrel{y_2}{-2}) \\\\\\ slope = m\implies \cfrac{\stackrel{rise}{ y_2- y_1}}{\stackrel{run}{ x_2- x_1}}\implies \cfrac{-2-0}{0-3}\implies \cfrac{-2}{-3}\implies \cfrac{2}{3} \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-0=\cfrac{2}{3}(x-3)\implies y=\cfrac{2}{3}x-2

3 0
3 years ago
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