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Anton [14]
3 years ago
15

Can someone help me do this darn work plz

Mathematics
2 answers:
PSYCHO15rus [73]3 years ago
5 0

Answer:

13. 17/20

14. 11/100

16.) 4 3/10

17.) 7 3/4

19.) -1 3/5-

20.) 3/8

22.) -5 3/5

23.) 1 3/25

26.) 85.33%

astraxan [27]3 years ago
4 0

Answer:

13. 17/20

14. 11/100

16. 4 3/10

17. 7 3/4

19. 1 3/50

20. 3/8

22. -5 3/5

23. 1 3/25

25. 6.34%

26. 85.33%

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Step-by-step explanation:

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3 0
4 years ago
Rewrite by completing the square f(x) = x2 - 6x +43
docker41 [41]

Answer:

f(x) = (x - 3)^2 + 34

Step-by-step explanation:

5 0
3 years ago
the tangent line to the curve y=x^3-6x^2-34x-9 has slope 2 at two points on the curve. find the two points
hichkok12 [17]
\bf y=x^3-6x^2-34x-9\implies \cfrac{dy}{dx}=3x^2-12x-34
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\stackrel{\textit{slope of 2}}{2}=3x^2-12x-34\implies 0=3x^2-12x-36
\\\\\\
0=x^2-4x-12\implies 0=(x-6)(x+2)\implies x=
\begin{cases}
6\\
-2
\end{cases}\\\\
-------------------------------\\\\
\stackrel{y}{f(6)}=(6)^3-6(6)^2-34(6)-9\implies f(6)=-213\\\\\\ (\stackrel{x}{6}~,~\stackrel{y}{-213})
\\\\\\
\stackrel{y}{f(-2)}=(-2)^3-6(-2)^2-34(-2)-9\implies f(-2)=27\\\\\\ (\stackrel{x}{-2}~,~\stackrel{y}{27})
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