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3 years ago

6

A school staff meeting had 55 teachers in attendance, 80% of whom were first-year teachers. How many first-year teachers were in

the meeting

1 answer:

frosja888 [35]3 years ago

3 0

Answer: 10

Step-by-step explanation:

Is 10 the answer

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its 76 degrees fahrenheit at the 6000-foot level of a mountain, and 49 degrees Fahrenheit at the 12000-foot level of the mountai

brilliants [131]

$T = \frac{-9}{2}x + 103$ is the linear equation to find the temperature T at an elevation x on the mountain, where x is in thousands of feet.

<em><u>Solution:</u></em>

The linear equation in slope intercept form is given as:

T = cx + k ------ (i)

Where "t" is the temperature at an elevation x

And x is in thousands of feet

<em><u>Given that its 76 degrees fahrenheit at the 6000-foot level of a mountain</u></em>

Given, when c = 6 thousand ft and $T = 76^{\circ}$ fahrenheit

This implies,

From (i)

76 = c(6) + k

76 = 6c + k

⇒ k = 76 - 6c ----- (ii)

<em><u>Given that 49 degrees Fahrenheit at the 12000-foot level of the mountain</u></em>

Given, when c = 12 thousand ft and $T = 49^{\circ}$ fahrenheit

This implies,

From (i)

49 = c(12) + k

49 = 12c + k

Substitute (ii) in above equation

49 = 12c + (76 - 6c)

49 = 12c + 76 - 6c

49 - 76 = 6c

6c = -27

$c = \frac{-9}{2}$

Substituting the value of c in (ii) we get

$k = 76 - 6( \frac{-9}{2})\\\\k = 76 + 27 = 103$

Substituting the value of c and k in (i)

$T = \frac{-9}{2}x + 103$

Where "x" is in thousands of feet

Thus the required linear equation is found

5 0

3 years ago

47 in = ? ft ? in<br><br> 3 ft 11 in<br><br> 4 ft 0 in<br><br> 3 ft 9 in<br><br> 564 ft 0 in

Veseljchak [2.6K]

Answer:

3ft 11 in

Step-by-step explanation:

1 foot equals 12 inches, 12 × 3 = 36 = 3 feet + 11 inches = 47 inches = 3ft 11in

8 0

3 years ago

Ignore circled one and work it out please

mash [69]

Answer:

a. $\frac{(x-7)}{x^2+x-30}$

Step-by-step explanation:

$\huge \frac{x^2-3x-28}{(x^2+10x+24)(x-5)} \\\\\huge {=\frac{x^2-7x+4x-28}{(x^2+6x+4x+24)(x-5)}}\\\\\huge {=\frac{x(x-7)+4(x-7)}{\{x(x+6)+4(x+6)\}(x-5)}}\\\\\huge {=\frac{(x-7)(x+4)}{(x+6)(x+4)(x-5)}}\\\\\huge {=\frac{(x-7)}{(x+6)(x-5)}}\\\\\huge {=\frac{(x-7)}{x^2+(6-5)x+6(-5)}}\\\\\huge {=\frac{(x-7)}{x^2+x-30}}$

3 0

3 years ago

The graph of the function f(x)=−4(x−3)2+9 will be a parabola opening in which direction?

sesenic [268]

Answer:

downwards

Step-by-step explanation:

the equation of a parabola in vertex form is

f(x) = a(x - h)² + k

where (h, k ) are the coordinates of the vertex and a is a multiplier

• if a > 0 then parabola opens upwards

• if a < 0 then parabola opens downwards

for

f(x) = - 4(x - 3)² + 9 with a = - 4 < 0 , then

the parabola opens downwards

8 0

2 years ago

6.<br> What is the midpoint of the line segment whose<br> endpoints (7,-4) and (-3, -2)?<br> are

quester [9]

Answer: (2, -3)

Step-by-step explanation:

To find the the answer, you will need to use the midpoint formula, which is as following:

(x₁+x₂/2, y₁+y₂/2)

Since we have two coordinates, let's substitute them into the equation.

(7 + (-3 )/ 2, (-4) + (-2)/2)

We should first add 7 and -3 together, as well as -4 and -2.

(4/2, -6/2)

We then divide 4 and -6 by 2. This would give us our midpoint coordinate.

(2, -3)

6 0

3 years ago