The is the concept of algebra, the weight of the spring can be modeled by the equation;
w=0.9sqrt E
where;
=energy in joules;
thus the weight of the spring when the energy is 12 j will be:
w=0.9sqrt12
w=3.18 g
Answer:
The surface area is 23
Step-by-step explanation:
Good Luck!
Answer:
Do you have any answer choices?
Step-by-step explanation:
Answer:
B: ![x>\frac{3}{2}](https://tex.z-dn.net/?f=x%3E%5Cfrac%7B3%7D%7B2%7D)
Step-by-step explanation:
![12\left(\frac{1}{2}x-\frac{1}{3}\right)>8-2x](https://tex.z-dn.net/?f=12%5Cleft%28%5Cfrac%7B1%7D%7B2%7Dx-%5Cfrac%7B1%7D%7B3%7D%5Cright%29%3E8-2x)
Expand:
![6x-4>8-2x](https://tex.z-dn.net/?f=6x-4%3E8-2x)
Add 4 to both sides:
![6x-4+4>8-2x+4](https://tex.z-dn.net/?f=6x-4%2B4%3E8-2x%2B4)
![6x>-2x+12](https://tex.z-dn.net/?f=6x%3E-2x%2B12)
Add 2x to both sides:
![6x+2x>-2x+12+2x](https://tex.z-dn.net/?f=6x%2B2x%3E-2x%2B12%2B2x)
![8x>12](https://tex.z-dn.net/?f=8x%3E12)
Divide both sides by 8:
![\frac{8x}{8}>\frac{12}{8}](https://tex.z-dn.net/?f=%5Cfrac%7B8x%7D%7B8%7D%3E%5Cfrac%7B12%7D%7B8%7D)
Hence,
(Option B)
I cannno t see that picture bud butttt hope this helps it is 643222 + ( . ) = 2