Answer:7
Step-by-step explanation:
Solution :
From the figure,
The coordinates of --
A = (-5,-3)
B = (-6,-1)
C = (-3,-1)
D = (-2,-3)
When it undergoes reflection about x-axis, we have the coordinates of the quadrilateral as
A' = (-5,+3)
B' = (-6,+1)
C' = (-3,+1)
D' = (-2,+3)
Now A'B'C'D' is translated 3 units to right, so the coordinates will be --
A" = (-2,3)
B" = (-3,1)
C" = (0,1)
D" = (1,3)
When the quadrilateral moves third and two units up, we get
A"' = (3,3)
B"' = (2,1)
C"' = (5,1)
D"' = (6,3)
The surface charge density:
S(igma) = Q / A
A = 1.6 * 10^(-2) * 1.6 * 10^(-2) = 2.56 * 10^(-4) m²
The electric field: E = S / E(psilon) o
E = 0.711 * 10^^(-9) / ( 2.56 * 10 ^(-4) * 8.85 * 10 ^(-12) ) =
= 0.3138 * 10 ^6 = 3.138 * 10^5 V/m
a ) Δ V = E d
Δ V = 3.138 * 10^5 V/m* 1.2 * 10^(-3) m = 376.56 V
b ) When d = 2.40 mm:
Δ V = 3.138 * 10^5 V/m * 2.40 *10^(-3) m = 753.12 V
Answer:that's easy
Step-by-step explanation: to find the length of the circle you times it you will find the answer