After thorough researching, if a jet in calm air conditions travels with velocity vector (389, 389) and the wind velocity (in mph) at the plane’s cruising altitude is given by (0, 50), then the plane’s true speed is 600 mph. The correct answer to the following given statement above is with the letter C.
The volume of Kuroshio Sea rank is 9450 cubic meters, if the sea tank is 27m long, 35m wide and 10m deep.
Step-by-step explanation:
The given is,
Kuroshio Sea tank is 27m long, 35m wide and 10m deep.
Step:1
Sea tank looks like a rectangular prism,
Formula to calculate the volume of rectangular prism,
.............................(1)
Where, w - Width of the rectangular prism
h - Height or depth of the rectangular prism
l - Length of the rectangular prism
From given,
w = 35 meters
l = 27 meters
h = 10 meters
Equation (1) becomes,



Volume of the sea tank, V = 9450 Cubic meters
Result:
The volume of Kuroshio Sea rank is 9450 cubic meters, if the sea tank is 27m long, 35m wide and 10m deep.
Answer: c > -25
From the question you can get the equation:
5 - 3c > 80; subtract 5 from both side
-3c > 75; divide -3 from both side
c > -25
So numbers including: -24, -23, -22, -21…
are all numbers that could work
draw a perpendicular line from the directrix passing through the focus, this will be the line of symmetry.
The vertex(h, k) will be located on the line half way between the focus and directrix.
The distance from the focus to the vertex is called the focal length, call it a. The then equation is
(x - h)^2 = 4a(y - k)
the equation can be manipulated to
y = 1/4a(x - h)^2 + k
hope it helps