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Licemer1 [7]
3 years ago
14

I need help on this question

Mathematics
1 answer:
Westkost [7]3 years ago
6 0

Answer:

v = 16.5

Step-by-step explanation:

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If 4 over 9 equals 2 over x , what do you know about their cross products?
goblinko [34]
If 4/9 = 2/x then my guess is x=18
4 0
4 years ago
Solve the system of equations:<br> y= 2x - 5<br> y=x^2-5<br><br> Apex
arlik [135]

Answer:

A is the answer

Step-by-step explanation:

(0, -5):

-5 = 2(0) - 5 >>>   -5 = -5

-5 = (0)^2 - 5 >>>   -5 = -5

(2, -1):

-1 = 2(2) - 5 >>>   -1 = 4 - 5 >>>   -1 = -1

-1 = (2)^2 - 5 >>>   -1 = 4 - 5 >>>   -1 = -1

4 0
3 years ago
Write 9x² - 36x = 4y² + 24y + 36 in standard form
Kisachek [45]

Answer:

9·x² - 36·x = 4·y² + 24·y + 36 in standard form is;

(x - 2)²/2² - (y + 3)²/3² = 1

Step-by-step explanation:

The standard form of a hyperbola is given as follows;

(x - h)²/a² - (y - k)²/b² = 1 or (y - k)²/b² - (x - h)²/a² = 1

The given equation is presented as follows;

9·x² - 36·x = 4·y² + 24·y + 36

By completing the square, we get;

(3·x - 6)·(3·x - 6) - 36 = (2·y + 6)·(2·y + 6)

(3·x - 6)² - 36 = (2·y + 6)²

(3·x - 6)² - (2·y + 6)² = 36

(3·x - 6)²/36 - (2·y + 6)²/36 = 36/36 = 1

(3·x - 6)²/6² - (2·y + 6)²/6² = 1

3²·(x - 2)²/6² - 2²·(y + 3)²/6² = 1

(x - 2)²/2² - (y + 3)²/3² = 1

The equation of the hyperbola  is (x - 2)²/2² - (y + 3)²/3² = 1.

5 0
3 years ago
Solve pls branliest!
olasank [31]
1) -7+3
2) -7 + (-3) …….
6 0
3 years ago
Read 2 more answers
Which equation represents the magnitude of an
Basile [38]

Answer:

M=\log{(100S)}

Step-by-step explanation:

The <em>Richter scale</em>, the standard measure of earthquake intensity, is a <em>logarithmic scale</em>, specifically logarithmic <em>base 10</em>. This means that every time you go up 1 on the Richter scale, you get an earthquake that's 10 times as powerful (a 2.0 is 10x stronger than a 1.0, a 3.0 is 10x stronger than a 2.0, etc.).

How do we compare two earthquake's intensities then? As a measure of raw intensity, let's call a "standard earthquake" S. What's the magnitude of this earthquake? The magnitude is whatever <em>power of 10</em> S corresponds to; to write this relationship as an equation, we can say 10^m=S, which we can rewrite in logarithmic form as m=\log{S}.

We're looking for the magnitude M of an earthquake 100 times larger than S, so reflect this, we can simply replace S with 100S, giving us the equation

M=\log{(100S)}.

To check to see if this equation is right, let's say we have an earthquake measuring a 3.0 on the Richter scale, so 3=\log{S}. Since taking 100 times some intensity is the same as taking 10 times that intensity twice, we'd expect that more intense earthquake to be a 5.0. We can expand the equation M=\log{(100S)} using the product rule for logarithms to get the equation

M=\log{(100S)}=\log{100}+\log{S}

And using the fact that \log{100}=2 and our assumption that \log{S}=3, we see that M=2+3=5 as we wanted.

3 0
4 years ago
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