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lesantik [10]
3 years ago
7

A 1 km long train travelling at a speed of 60km/h enter a tunnel 1km long. What time will the train take to come out of the tunn

el fully.​
Mathematics
1 answer:
zysi [14]3 years ago
3 0

Answer:

2 minutes

Step-by-step explanation:

The front of the train enters the tunnel and travels 1 km before the rear of the train enters the tunnel.  Thus, the total distance traveled by the front of the train is 2 km, and this is covered in a certain number of hours:

Since distance = rate times time, time = distance / rate.  In this particular case we have:

                                              2 km

time = distance / rate = ------------------- = (1/30) hr

                                           60 km/hr

(1/30) hr converts to 2 minutes, since 1 hr = 60 minutes

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Determine the number of zeros of the polynomial function <br> F(x) = x^4 - x^7
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7

Step-by-step explanation:

Using fundamental theorem of algebra, there should be 7 roots, if you count multiplicity.

If you're only counting distinct roots, then there should be 4 roots.

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an architect is building a seminar hall to seat 1450 people. he wants the seating to be such that the number of rows and the num
Lady_Fox [76]
The seats must be arranged in a 38 by 39 arrangement to have the minimum amount of seats used.
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3 years ago
Please help!! 10-|-5-2|
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Answer:

3

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5 0
3 years ago
What multiplies to -900 and adds to 5?
liq [111]
Xy = -900
x + y = 5

     x + y = 5
x - x + y = -x + 5
           y = -x + 5

                                                xy = -900
                                      x(-x + 5) = -900
                                  x(-x) + x(5) = -900
                                       -x² + 5x = -900
                             -x² + 5x + 900 = 0
               -1(x²) - 1(-5x) - 1(-900) = 0
                          -1(x² - 5x - 900) = 0
                                       -1            -1
                               x² - 5x - 900 = 0
                               x = -(-5) ± √((-5)² - 4(1)(-900))
                                                      2(1)
                               x = 5 ± √(25 + 3600)
                                                  2
                               x = 5 ± √(3625)
                                             2
                               x = 5 ± 5√(145)
                                           2
                               x = 2.5 ± 2.5√(145)

                          x + y = 5
   2.5 ± 2.5 √(145) + y = 5
- (2.5 ± 2.5√(145)       - (2.5 ± 2.5√(145)
                                y = 2.5 ± 2.5√(145)
                          (x, y) = (2.5 ± 2.5√(145), 2.5 ± 2.5√(145))

The two numbers that add up to 5 and multiply to -900 are 2.5 ± 2.5√(145).
6 0
3 years ago
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