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lesantik [10]
2 years ago
7

A 1 km long train travelling at a speed of 60km/h enter a tunnel 1km long. What time will the train take to come out of the tunn

el fully.​
Mathematics
1 answer:
zysi [14]2 years ago
3 0

Answer:

2 minutes

Step-by-step explanation:

The front of the train enters the tunnel and travels 1 km before the rear of the train enters the tunnel.  Thus, the total distance traveled by the front of the train is 2 km, and this is covered in a certain number of hours:

Since distance = rate times time, time = distance / rate.  In this particular case we have:

                                              2 km

time = distance / rate = ------------------- = (1/30) hr

                                           60 km/hr

(1/30) hr converts to 2 minutes, since 1 hr = 60 minutes

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Step-by-step explanation:

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How to find cp if loss and sp are given​
velikii [3]

Step-by-step explanation:

\tt{ \: H \: E \: Y \: \:  T \: H \: E \: R\: E \: } !

When Loss and Selling price ( SP ) are given , Cost price ( CP ) can be found out using the following formulae :

✰ \large{ \boxed{ \boxed{ \tt{CP = Loss + SP}}}}

\text{How \: did\: we \:get  \:the \: formula :  \: CP \:  = Loss \:  +  \: SP} \: ?

We simply derived the formula from Loss = CP - SP.

First , Swap the sides of the equation :

⟶ \text{CP - SP = Loss}

Move SP to right hand side and change it's sign :

⟶\text{CP = Loss + SP}

This is how , CP can be obtained when we are given loss and SP.

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Have a wonderful day / night ! ツ

# \underbrace{ \tt{C \: a \: r \: r \: y \:  \: O \:n \:  \: L \: e \: a \: r \: n \: i \: n \: g}} !!

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