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Schach [20]
3 years ago
10

Find the mean of the day 10.25‚9‚4.75‚8‚2.65‚12‚2.35​

Mathematics
1 answer:
Genrish500 [490]3 years ago
4 0

Answer:

7!

Step-by-step explanation:

If you add all of those numbers together it would be 49!

Then you divide that number how many numbers there are.

There are 7 numbers and 49/7 =7!

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W is less than 8 but greater than -3.
Svetradugi [14.3K]

Answer:

W= a number greater then -3= -2,-1,0,1,2,3,4,5,6,7,8,9,10...

Step-by-step explanation:

4 0
3 years ago
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<img src="https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B32%7D" id="TexFormula1" title="\sqrt[3]{32}" alt="\sqrt[3]{32}" align="absmid
Elza [17]
Answer

If you would like it in numbers it would be 16.970562748

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2 years ago
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A temperature recorded in antarctica was -116 degrees fahrenheit. The teMPTURE rECORED iN tHE sHArA dESERT iS 131 dEGREES fAHREN
Natalka [10]

Step-by-step explanation:

Go from the negetive number to 0 to the positive number. -116 to 0 is 116. Then, 0 to 131 is 131. Do 116+131 then you will find your answer.

Hope this helps.  

7 0
3 years ago
Which function is represented by the graph above ?
allochka39001 [22]

Answer:

one to one function is denoted by the graph

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3 years ago
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We often deal with weighted​ means, in which different data values carry different weights in the calculation of the mean. For​
Veseljchak [2.6K]

Answer:

a) The student's overall average for the class is 87.97.

b) He would need a score above 100 to get an A, which means that he could not have scored high enough on the final exam to get an A in the class.

Step-by-step explanation:

Weighed average:

To solve this question, we find the student's weighed average, multiplying each of his grade by his weights.

Grades and weights:

Scored 82.5 on the midterm, worth 30%.

Scored 88.6 on the final exam, worth 30%.

Scored 91.6 on the homework, worth 40%.

a. On a 100-point scale, what is the student's overall average for the class?

Multiplying each grade by it's weight:

A = 82.5*0.3 + 88.6*0.3 + 91.6*0.4 = 87.97

The student's overall average for the class is 87.97.

b. The student was hoping to get an A in the class, which requires an overall score of 93.5 or higher. Could he have scored high enough on the final exam to get an A in the class?

Score of x on the final class, and verify that the average could be 93.5 or higher. So

A = 82.5*0.3 + 88.6*0.3 + 0.4x

A \geq 93.5

82.5*0.3 + 88.6*0.3 + 0.4x \geq 93.5

0.4x \geq 93.5 - (82.5*0.3 + 88.6*0.3)

x \geq \frac{93.5 - (82.5*0.3 + 88.6*0.3)}{0.4}

x \geq 105.425

He would need a score above 100 to get an A, which means that he could not have scored high enough on the final exam to get an A in the class.

3 0
3 years ago
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