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Sunny_sXe [5.5K]
3 years ago
9

What integer values satisfy both inequalities? -3 < X < 2 I > -1

Mathematics
1 answer:
kondaur [170]3 years ago
7 0

Answer:

1?

Step-by-step explanation:

not sure if it's correct or not but ok

You might be interested in
If a number is not a natural number then it is not a whole number
Alisiya [41]

Answer:

no

Step-by-step explanation:

a natural number has to be a whole number

4 0
3 years ago
X + 5y = 8<br> -x + 2y = -1<br> How is this solved?
Oksi-84 [34.3K]
Add both the equations together to eliminate x

x+5y=8
-x+2y=-1

7y=7
y=1

Now fill in y into the original equation

x+5(1)=8
x+5=8
x=3

Now you can check by filling x and y into the second equation.

-(3)+2(1)=-1
-3+2=-1
-1=-1

So your answer will be (3, 1)

Brainliest my answer if it helps you out?
8 0
3 years ago
is vector v with an initial point of (-5,22) and a terminal point of (20,60) equal to vector u with an intintal point of (50,120
marta [7]

Answer:

Yes, vectors u and v are equal.

Step-by-step explanation:

We need to check whether vectors u and v are equal or not.

If the initial point is (x_1,y_1) and terminal point is (x_2,y_2), then the vector is

Vector=(x_2-x_1)i+(y_2-y_1)j

Vector v with an initial point of (-5,22) and a terminal point of (20,60).

\overrightarrow v=(20-(-5))i+(60-22)j

\overrightarrow v=25i+38j       ..... (1)

Vector u with an initial point of (50,120) and a terminal point of (75,158).

\overrightarrow u=(75-50)i+(158-120)j

\overrightarrow u=25i+38j         .... (2)

From (1) and (2) we get

\overrightarrow u=\overrightarrow v

Therefore, vectors u and v are equal.

5 0
3 years ago
(20 points)<br> Question from Similarity
Mariana [72]

Answer:

45 is the anwser

Step-by-step explanation:

thank you

7 0
3 years ago
If f(x) = 2x^2-x-6 and g(x) = x^2-4 , what is the domain of f(x) divided by g(x)
Gelneren [198K]
(2x^2-x-6)/x^2-4

Factor top and bottom and you get

(2x+3)(x-2)/(x+2)(x-2)

The (x-2) cancel out each other leaving,

(2x+3)/x+2

The domain is all real numbers EXCEPT for -2. The domain can never be -2 as it would to the bottom having a zero, and that can't happen


5 0
3 years ago
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