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Eddi Din [679]
2 years ago
8

If A is the set of prime numbers and B is the set of

Mathematics
1 answer:
Natasha2012 [34]2 years ago
7 0

The correct option is (A) None.

The numbers of digits that are common to both sets is none.

<h3>What are sets?</h3>

In mathematics, a set is a group of distinct objects that form a group. A set can contain any type of group of items, such as a grouping of numbers, days of the week, vehicle types, and so on.

  • Each element inside the set is referred to as a set element. When writing a set, curly brackets are used.
  • A simple instance of a set could be as follows. Set A = {1,2,3,4,5}. A set's elements can be represented in a variety of ways.
  • A roster form or even a set builder form is typically used to represent sets.

Now, according to the question;

Set A =  {1,3,5,7,11,13,17,19,......} Prime Number Collection (The numbers which have only two factors i.e, 1 and the number itself)

Set B {15,25,35,45,55,......} Set of two-digit positive integers with the unit digit ("5").

Each two-digit positive integer with such a unit digit of 5 has much more than two factors; Set B has 1,5 as well as "itself" as factors.

As a result, these two sets are disjoint sets (no common element).

To know more about sets, here

brainly.com/question/24462379

#SPJ4

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exis [7]

Answer: The range is 55.

Step-by-step explanation:

8 0
3 years ago
Find the value of x.<br> Please help me!!!!!!
Katen [24]

Answer:

I think this will help you.

Step-by-step explanation:

hi This will help you to do this

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3 0
3 years ago
A manufacturer makes ball bearings out of motel steel. it takes 5.24 cubic centimeters of molten steel to make ball bearings tha
katrin2010 [14]

Using volume of ball bearings, a manufacturer makes 10 ball bearings from 5.2 cm³ of molten steel to make ball bearings that each have a diameter of 1 centimeter.

According to the question,

It takes 5.24 cubic centimeters of molten steel to make ball bearings that each have a diameter of 1 centimeter.

Radius = 1/2 = 0.5 cm

volume V of one ball bearing is: V=(4/3)*π*r³

= 4/3 * π * (0.5)³

=0.524 cm³

In order to find number of ball bearings out of molten steel only if we divide the volume of steel by the volume of the ball bearing

5.24/0.524=10.

Hence, using volume of ball bearings, a manufacturer makes 10 ball bearings from 5.2 cm³ of molten steel to make ball bearings that each have a diameter of 1 centimeter.

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4 0
2 years ago
What is the area of quadrilateral QRST if QS=18 and RT=24. Show work.
lana [24]

Answer:

\text{Area of quadrilateral QRST}=216

Step-by-step explanation:

Please find the attached image for the quadrilateral QRST.

We have been given that QS=18 \text{ and } RT=24. We are asked to find the area of quadrilateral QRST.

Upon looking at the image of quadrilateral QRST, we can see that quadrilateral QRST is a kite as it has one pair of diagonally opposite equal angles (98 degrees).

We know that area of kite is equal to half the product of its diagonal.

We can see from our image that QS and RT are diagonal of kite, so the area of quadrilateral QRST would be:

\text{Area of quadrilateral QRST}=\frac{QS\cdot RT}{2}

\text{Area of quadrilateral QRST}=\frac{18\cdot 24}{2}

\text{Area of quadrilateral QRST}=\frac{432}{2}

\text{Area of quadrilateral QRST}=216

Therefore, the area of quadrilateral QRST is 216 square units.

3 0
3 years ago
Using a directrix of y = −3 and a focus of (2, 1), what quadratic function is created?
bazaltina [42]
<span>f(x) = one eighth (x - 2)^2 - 1
   Since a parabola is the curve such that all points on the curve have the same distance from the directrix as the distance from the point to the focus.With that in mind, we can quickly determine 3 points on the parabola. The 1st point will be midway between the focus and the directrix, So: (2, (1 + -3)/2) = (2, -2/2) = (2,-1). The other 2 points will have the same y-coordinate as the focus, but let offset on the x-axis by the distance from the focus to the directrix. Since the distance is (1 - -3) = 4, that means the other 2 points will be (2 - 4, 1) and (2 + 4, 1) which are (-2, 1) and (6, 1). The closest point to the focus will have the same x-coordinate as the focus, so the term will be (x-2)^2. This eliminates the functions "f(x) = -one eighth (x + 2)^2 - 1" and "f(x) = -one half (x + 2)^2 - 1" from consideration since their x term is incorrect, leaving only "f(x) = one eighth (x - 2)^2 - 1" and "f(x) = one half (x - 2)^2 + 1" as possible choices. Let's plug in the value 6 for x and see what y value we get from squaring (x-2)^2. So: (x-2)^2 (6-2)^2 = 4^2 = 16 Now which option is equal to 1? Is it one eighth of 16 minus 1, or one half of 16 plus 1? 16/8 - 1 = 2 - 1 = 1 16/2 + 1 = 8 + 1 = 9 Therefore the answer is "f(x) = one eighth (x - 2)^2 - 1"</span>
3 0
4 years ago
Read 2 more answers
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