14 Bc 6.5 + 6.5 = 12 + 1/2+1/2 = 13
Answer as a fraction: AB = 127/13 (exact)
Answer in decimal form: AB = 9.76923 (approximate)
Sides AC and BC are the same length as AB.
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Work Shown:
AB = (3/2)x+4
AC = (1/5)x+9
These sides are equal to each other since all sides of an equilateral triangle are the same length.
AB = AC
(3/2)x+4 = (1/5)x+9
10*[ (3/2)x+4 ] = 10*[ (1/5)x+9 ] ... see note below
10*(3/2)x + 10*4 = 10*(1/5)x + 10*9
15x + 40 = 2x + 90
15x-2x = 90-40
13x = 50
x = 50/13
Note: I multiplied both sides by the LCD (lowest common denominator) 10 to clear out the fractions.
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Once we know what x is, we plug it into the expression for AB
AB = (3/2)x+4
AB = (3/2)*(50/13) + 4
AB = (3*50)/(2*13) + 4
AB = (3*2*25)/(2*13) + 4
AB = (3*25)/(13) + 4
AB = 75/13 + 4
AB = 75/13 + 52/13
AB = (75+52)/13
AB = 127/13 which is exact
AB = 9.76923 which is approximate
Because we have an equilateral triangle, AB = BC = AC.
The probability of winning a game of checkers against your friend is 67%.
<h3>What is the probability of winning a game of checkers against my friend?</h3>
Probability can be described as the process of determining the chances of an event happening. The chances that an event would occur has a value that lies between 0 and 1. A value of 0 is given when the event does not occur and a value of 1 if the event occurs.
The probability of winning a game of checkers = probability of winning both games / probability of winning a game of chess
20% / 30% = 67%
To learn more about probability, please check: brainly.com/question/26321175
Answer:
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Step-by-step explanation:
Under a clockwise rotation about the origin of 90°
a point (x, y ) → (y, - x ) , thus
X(- 1, - 3 ) → X'(- 3, 1 )
Y(0, 0 ) → Y'(0, 0 )
Z(1, - 3 ) → Z'(- 3, - 1 )
You haven't provided the original coordinates or the figure, therefore, I cannot give an exact answer. However, I will help you with the concept.
For rotation 180° about the origin, the signs of both the x any y coordinates are changed.
<u>This can be modeled as follows:</u>
(x,y) ......> rotation 180° about the origin ........> (-x,-y)
<u>Examples:</u>
(1,2) .......> rotation 180° about the origin ........> (-1,-2)
(2,-19) ....> rotation 180° about the origin ........> (-2,19)
(-3,-8) .....> rotation 180° about the origin ........> (3,8)
(-5,7) ......> rotation 180° about the origin ........> (5,-7)
Based on the above, all you have to do to get the coordinates of C' is change the signs of both the x and y coordinates
Hope this helps :)
