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Leokris [45]
3 years ago
9

Solve 2x +7y = 4 for y

Mathematics
1 answer:
Lapatulllka [165]3 years ago
7 0

Answer:

y = 4/7 - 2/7x

Step-by-step explanation:

Hope it's correct :D

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Helppp! Again! Please!!
erastovalidia [21]

Answer:

pretty sure its 6, i think

6 0
3 years ago
in a particular class of 23 students, 18 are men. what fraction of the students in the class are men?k
Mademuasel [1]
It gave you the answer for men they said their were 18 men out of 23 so are they asking for women or actually men cause if it was that it would be 18/23
7 0
3 years ago
Use the functions f(x) and g(x) to answer the question.
kenny6666 [7]
f(x)=x^2+3\\\\g(x)=x-7\\\\(f+g)(x)=f(x)+g(x)=(x^2+3)+(x-7)=x^2+x-4

Answer: C)

6 0
3 years ago
The time needed to complete a final examination in a particular college course is normally distributed with a mean of 77 minutes
Komok [63]

Answer:

a. The probability of completing the exam in one hour or less is 0.0783

b. The probability that student will complete the exam in more than 60 minutes but less than 75 minutes is 0.3555

c. The number of students will be unable to complete the exam in the allotted time is 8

Step-by-step explanation:

a. According to the given we have the following:

The time for completing the final exam in a particular college is distributed normally with mean (μ) is 77 minutes and standard deviation (σ) is 12 minutes

Hence, For X = 60, the Z- scores is obtained as follows:

Z=  X−μ /σ

Z=60−77 /12

Z=−1.4167

Using the standard normal table, the probability P(Z≤−1.4167) is approximately 0.0783.

P(Z≤−1.4167)=0.0783

Therefore, The probability of completing the exam in one hour or less is 0.0783.

b. In this case For X = 75, the Z- scores is obtained as follows:

Z=  X−μ /σ

Z=75−77 /12

Z=−0.1667

Using the standard normal table, the probability P(Z≤−0.1667) is approximately 0.4338.

Therefore, The probability that student will complete the exam in more than 60 minutes but less than 75 minutes is obtained as follows:

P(60<X<75)=P(Z≤−0.1667)−P(Z≤−1.4167)

=0.4338−0.0783

=0.3555

​

Therefore, The probability that student will complete the exam in more than 60 minutes but less than 75 minutes is 0.3555

c. In order to compute  how many students you expect will be unable to complete the exam in the allotted time we have to first compute the Z−score of the critical value (X=90) as follows:

Z=  X−μ /σ

Z=90−77 /12

Z​=1.0833

UsING the standard normal table, the probability P(Z≤1.0833) is approximately 0.8599.

Therefore P(Z>1.0833)=1−P(Z≤1.0833)

=1−0.8599

=0.1401

​

Therefore, The number of students will be unable to complete the exam in the allotted time is= 60×0.1401=8.406

The number of students will be unable to complete the exam in the allotted time is 8

6 0
3 years ago
You invest $1,100 in an account that has an annual interest rate of 2.1%, compounded continuously. How much money will be in the
uranmaximum [27]
$1100 x 1.021^7 = $1272 (whole number.)

the $1100 is the original amount of money put in the bank with the 1.021 being the interest rate. this was put to the power of 7 to represent the years the money will be in the account.
6 0
3 years ago
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