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3 years ago

(I'd like the quick and short answer please a long explaination is unnecessary)

Mathematics

1 answer:

professor190 [17]3 years ago

5 0

Answer:

(-3;-2)

Step-by-step explanation:

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What is the greatest common factor of x^4 and x^5?

Naily [24]

Answer:

x^4

Explanation:

Breakdown x^4 = x · x · x · x

Breakdown x^5 = x · x · x · x · x

Here the common factor is x · x · x · x = x^4

Hence, the greatest common factor of x^4 and x^5 is x^4.

8 0

1 year ago

The service department of a luxury car dealership conducted research on the amount of time its service technicians spend on each

mart [117]

Answer:

Probability that the mean service time is between 1 and 2 hours is 0.96764.

Step-by-step explanation:

We are given that a systematic random sample of 100 service appointments has been collected.

The 100 appointments showed an average preparation time of 90 minutes with a standard deviation of 140 minutes.

Let $\bar X$ = sample mean service time

The z-score probability distribution for sample mean is given by;

Z = $\frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } }$ ~ N(0,1)

where, $\mu$ = average preparation time = 90 minutes

$\sigma$ = standard deviation = 140 minutes

n = sample of appointments = 100

The Z-score measures how many standard deviations the measure is away from the mean. After finding the Z-score, we look at the z-score table and find the p-value (area) associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X.

Now, probability that the mean service time is between 60 and 120 minutes is given by = P(60 minutes < $\bar X$ < 120 minutes)

P(60 minutes < $\bar X$ < 120 minutes) = P( $\bar X$ < 120 min) - P( $\bar X$ $\leq$ 60 min)

P( $\bar X$ < 120 min) = P( $\frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } }$ < $\frac{120-90}{\frac{140}{\sqrt{100} } }$ ) = P(Z < 2.14) = 0.98382

P( $\bar X$ $\leq$ 60 min) = P( $\frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } }$ $\leq$ $\frac{60-90}{\frac{140}{\sqrt{100} } }$ ) = P(Z $\leq$ -2.14) = 1 - P(Z < 2.14)

= 1 - 0.98382 = 0.01618

The above probability is calculated by looking at the value of x = 2.14 in the z table which has an area of 0.98382.

Therefore, P(60 min < $\bar X$ < 120 min) = 0.98382 - 0.01618 = 0.96764

7 0

3 years ago

Explain two ways to find the LCM

svp [43]

Answer:

1. List the first several multiples of each number.

Look for multiples common to both lists. ...

Look for the smallest number that is common to both lists.

This number is the LCM.

Find the GCF for the two numbers.

Divide that GCF into the either number; it doesn't matter which one you choose, so choose the one that's easier to divide.

Take that answer and multiply it by the other number.

Step-by-step explanation:

Hope this helps!

4 0

3 years ago

What is the value of a?

ehidna [41]

Answer:

I think it's a= 6.98 I did the solution

4 0

2 years ago

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Ryan uses 2 3/4 cups of oil to make 6 servings of French fries. What fraction of a cup of oil did he use for one serving of Fren

Doss [256]

You need to make this in a mixed number form.

5 0

3 years ago