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Ivenika [448]
3 years ago
11

Find the midpoint of the segment with the following endpoints. (9,6) and (5,2)

Mathematics
2 answers:
kodGreya [7K]3 years ago
8 0

Answer:

M(7 ; 4)

Step-by-step explanation:

midpoint -M

M(\frac{x_{1}+x_{2}}{2} ; \frac{y_{1}+y_{2}}{2}  )

M(\frac{9+5}{2} ; \frac{6+2}{2}  )

M(7 ; 4)

Fantom [35]3 years ago
5 0

Answer:

(7, 4 )

Step-by-step explanation:

Given endpoints (x₁, y₁ ) and (x₂, y₂ ) then the midpoint is

( \frac{x_{1}+x_{2}  }{2} , \frac{y_{1}+y_{2}  }{2} )

Here (x₁, y₁ ) = (9, 6) and (x₂, y₂ ) = (5, 2) , then

midpoint = ( \frac{9+5}{2} , \frac{6+2}{2} ) = (\frac{14}{2} , \frac{8}{2} ) = (7, 4 )

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aivan3 [116]

Answer:

a. p(orange) = 5/14

b. p(green) = 3/14

c. p(red) = 1/7  

d. p(brown) = 2/7  

e. p(brown or red) = 3/7

Step-by-step explanation:

1. You have a 14 pencils. Two pencils are red, 5 pencils are orange, 3 pencils are green and 4 pencils are brown.

p(color) = (number of pencils of that color)/(total number of pencils)

p(color) = (number of pencils of that color)/14

a. If a pencil is picked at random, what is the probability that the pencil

will be orange?

p(orange) = 5/14

b. If a pencil is picked at random, what is the probability that the pencil

will be green?

p(green) = 3/14

c. If a pencil is picked at random, what is the probability that the pencil will be red?

p(red) = 2/14 = 1/7

d. If a pencil is picked at random, what is the probability that the pencil

will be brown?

p(brown) = 4/14 = 2/7

e. If a pencil is picked at random, what is the probability that the pencil

will be brown or red?

brown: 4

red: 2

brown or red: 4 + 2

p(brown or red) = 6/14 = 3/7

3 0
3 years ago
Choose True Or False <br><br>Question #1. <br>(3×5)+(5×5)=8×5<br><br>Question #2.<br>(3×2)+(8×3)=8×5
lions [1.4K]
1: True

This is because <span>(3×5)+(5×5)=40, and 8x5=40
</span>

2: False

This is because <span>(3×2)+(8×3)=30, not 40.



I hope i helped :)</span>
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