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Darina [25.2K]
3 years ago
15

Please i need help for all of them!!​

Mathematics
1 answer:
lianna [129]3 years ago
3 0

Answer:

1) x=65

2) x= 70

3) x= 40

4) x= 131

5) x= 75

6) x= 49

7) x= -12

8) x= 42

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Based on the demand graph and the supply graph shown above, what is the price at the point of equilibrium?
Vesna [10]

B. 70

I took the test on Edge 2022

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PLEASEEEEEEE HELP!!!!!
Aleks [24]

Answer:

22.18

Step-by-step explanation:

c squared = a squared + b squared - 2ab cos c

or a instead of c in this case.

144+225-360(-0.342)

square root 492.12

3 0
3 years ago
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Mrs. Robbins has stickers and erasers in her desk. The ratio of stickers to erasers is 3 to 8. She has 12 stickers. *
Nuetrik [128]
Given:
ratio of stickers to erasers: 3 to 8
She has 12 stickers.

3:8 = 12:x
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Mrs. Robbins has 32 erasers.

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3 years ago
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NOT SURE PLEASE HELP​
777dan777 [17]
2 units i believe but not entirely sure
4 0
3 years ago
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An automobile manufacturer has discovered that 20% of all the transmissions it installed in a particular style of truck are defe
Hatshy [7]

Answer:

0.148 = 14.8% probability that they will need to order at least one more new transmission

Step-by-step explanation:

For each transmission, there are only two possible outcomes. Either it is defective after a year of use, or it is not. The probability of a transmission being defective is independent of any other transmission. This means that the binomial probability distribution is used to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

20% of all the transmissions it installed in a particular style of truck are defective after a year of use.

This means that p = 0.2

Sold seven trucks:

This means that n = 7

It has two of the new transmissions in stock. What is the probability that they will need to order at least one more new transmission?

This is the probability that at least 3 are defective, that is:

P(X \geq 3) = 1 - P(X < 3)

In which

P(X < 3) = P(X = 0) + P(X = 1) + P(X = 2)

So

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{7,0}.(0.2)^{0}.(0.8)^{7} = 0.2097

P(X = 1) = C_{7,1}.(0.2)^{1}.(0.8)^{6} = 0.3670

P(X = 2) = C_{7,2}.(0.2)^{2}.(0.8)^{5} = 0.2753

P(X < 3) = P(X = 0) + P(X = 1) + P(X = 2) = 0.2097 + 0.3670 + 0.2753 = 0.852

P(X \geq 3) = 1 - P(X < 3) = 1 - 0.852 = 0.148

0.148 = 14.8% probability that they will need to order at least one more new transmission

6 0
3 years ago
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