Answer:
w = -1.7
General Formulas and Concepts:
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
Equality Property
Step-by-step explanation:
<u>Step 1: Define</u>
5(w + 2.2) - 4w = 9.3
<u>Step 2: Solve for </u><em><u>w</u></em>
- Distribute 5: 5w + 11 - 4w = 9.3
- Combine like terms: w + 11 = 9.3
- Isolate <em>w</em>: w = -1.7
<u>Step 3: Check</u>
<em>Plug in w into the original equation to verify it's a solution.</em>
- Substitute in <em>w</em>: 5(-1.7 + 2.2) - 4(-1.7) = 9.3
- (Parenthesis) Add: 5(0.5) - 4(-1.7) = 9.3
- Multiplication: 2.5 + 6.8 = 9.3
- Addition: 9.3 = 9.3
Here we see that 9.3 does indeed equal 9.3.
∴ w = -1.7 is the solution to the equation.
50-45=5
(5/6x)=5
Divide to get X=6
Answer:
C
Step-by-step explanation:
Answer:
0
Step-by-step explanation
The company started off with $10 in the first section(quarter). They lost (subtract)$15 in the second section, In the third section they lost (subtract)$20. In the final section they gained (plus) a profit of $25.
10-15-20+25=0
Answer:
Why do you keep sending the same question over and over again?
Step-by-step explanation:
Total Time Taken = 16secs
10a). We're asked to calculate the rate of speed change for the first 5secs.
This is another way of saying "Calculate Acceleration" in the first 5sec of Motion.
Why?
Acceleration is the rate of change of speed or the rate at which speed changes.
acceleration = v - u/t
where v = Final Speed
u = initial Speed.
Looking at the graph
You see that
Initial speed(u) = 1m/s
Final Speed(v) = 9m/s
t = 5secs
Acceleration = 9 - 1/ 5
a = 8/5
a = 1.6m/s².✅
10b)
We're asked to calc "t" from the graph.
Given that the acceleration at "t" untill 16sec(end of motion) is 2m/s².
This simply means that Constant Acceleration was held from "t" to the end of the Motion.
Do not confuse Constant Acceleration for Constant Velocity.
At Constant Velocity... Acceleration is zero(0)
At Constant Acceleration...Velocity Changes Uniformly or at the same rate each second and this is what we're dealing with in this question.
Taking the same step as we used in calculating acceleration above
Given a= 2m/s²
a = v - u/∆t
Where ∆t means time change or difference.
From "t" to 16
The change in time is 16 - "t"
2 = 21 - 9/( 16 - t)
2 = 12/16-t
16-t = 12/2
16 - t = 6
t = 16 - 6
t = 10secs.✅
Have a great Day!.