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adelina 88 [10]

2 years ago

12

Help me i dong get this that much

1 answer:

KengaRu [80]2 years ago

8 0

Answer:

ye

Step-by-step explanation:

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What fraction is equivalent to 42.8181

erica [24]

The answer will be A. 471/11. Hope it help!

4 0

3 years ago

Which values of a and b make the equation true

bixtya [17]

Love your profile pic

5 0

3 years ago

Differentiate Functions of Other Bases In Exercise, find the derivative of the function.

WARRIOR [948]

Answer:

$\dfrac{dy}{dx} =\dfrac{2 x + 6}{ \log{\left (10 \right )}\left(x^{2} + 6 x\right)}$

Step-by-step explanation:

given

$y = \log_{10}{(x^2+6x)}$

using the property of log $\log_ab=\frac{log_cb}{log_ca}$ , and if c = $e$ , $\log_ab=\frac{ln{b}}{ln{a}}$ , we can rewrite our function as:

$y = \dfrac{\ln{\left (x^{2} + 6 x \right )}}{\ln{\left (10 \right )}}$

now we can easily differentiate:

$\dfrac{dy}{dx} = \dfrac{1}{\ln{10}}\left(\dfrac{d}{dx}(\ln{(x^{2} + 6x)})\right)$

$\dfrac{dy}{dx} = \dfrac{1}{\ln{10}}\left(\dfrac{2x+6}{x^{2} + 6x}\right)$

$\dfrac{dy}{dx} =\dfrac{2 x + 6}{ \log{\left (10 \right )}\left(x^{2} + 6 x\right)}$

This is our answer!

3 0

3 years ago

Read 2 more answers

Simplify 3a + 4b + 5c + (-2a) + b

ad-work [718]

Answer:

<em> </em><em>a </em><em>+</em><em> </em><em>5</em><em>b</em><em> </em><em>+</em><em> </em><em>5</em><em>c</em>

Step-by-step explanation:

here's your solution

=> 3a + 4b + 5c +(-2a) + b

=> solve for like term

=> 3a - 2a + 4b + b + 5c

=> a + 5b + 5c

hope it helps

7 0

3 years ago

Read 2 more answers

The length and width of a rectangle are measured as 55 cm and 49 cm, respectively, with an error in measurement of at most 0.1 c

valentina_108 [34]

Answer:

The maximum error in the calculated area of the rectangle is $10.4 \:cm^2$

Step-by-step explanation:

The area of a rectangle with length $L$ and width $W$ is $A= L\cdot W$ so the differential of <em>A</em> is

$dA=\frac{\partial A}{\partial L} \Delta L+\frac{\partial A}{\partial W} \Delta W$

$\frac{\partial A}{\partial L} = W\\\frac{\partial A}{\partial W}=L$ so

$dA=W\Delta L+L \Delta W$

We know that each error is at most 0.1 cm, we have $|\Delta L|\leq 0.1$ , $|\Delta W|\leq 0.1$ . To find the maximum error in the calculated area of the rectangle we take $\Delta L = 0.1$ , $\Delta W = 0.1$ and $L=55$ , $W=49$ . This gives

$dA=49\cdot 0.1+55 \cdot 0.1$

$dA=10.4$

Thus the maximum error in the calculated area of the rectangle is $10.4 \:cm^2$

4 0

3 years ago