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2 years ago

PLEASE HELP (100 POINTS)

Mathematics

1 answer:

omeli [17]2 years ago

6 0

$\\ \rm\Rrightarrow 2sin^2x=1-cosx$

$\\ \rm\Rrightarrow 2sin^2x=1-1+sin^2x$

$\\ \rm\Rrightarrow 2sin^2x-sin^2x=0$

$\\ \rm\Rrightarrow sin^2x=0$

$\\ \rm\Rrightarrow sinx=0$

$\\ \rm\Rrightarrow x\in n\pi$

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