Question

PLEASE HELP (100 POINTS)

Answer 1

$\\ \rm\Rrightarrow 2sin^2x=1-cosx$

$\\ \rm\Rrightarrow 2sin^2x=1-1+sin^2x$

$\\ \rm\Rrightarrow 2sin^2x-sin^2x=0$

$\\ \rm\Rrightarrow sin^2x=0$

$\\ \rm\Rrightarrow sinx=0$

$\\ \rm\Rrightarrow x\in n\pi$