If B is the midpoint of AC, then |AB| = |AC|.
|AB| = 3x + 2
|BC| = 5x - 10
Therefore we have the equation:
3x + 2 = 5x - 10 |subtract 2 from both sides
3x = 5x - 12 |subtract 5x from both sides
-2x = -12 |divide both sides by (-2)
x = 6
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We have to give counter example for the given statement:
"The difference between two integers is always positive"
This statement is not true. As integers is the set of numbers which includes positive and as well as negative numbers including zero.
Consider any two integers say '2' and '-8'. Now, let us consider the difference between these two integers.
So, 2 - 8
= -6 which is not positive.
Therefore, it is not necessary that the difference of two integers is only positive. The difference of two integers can be positive, negative or zero.
Hope it can help u!!!!!!!
Applying the definition of an angle bisector, the value of x is: 11.
<h3>What is an Angle Bisector?</h3>
When a line segment bisects an angle into two equal halves, it is called an angle bisector. The two small angles formed have equal measure.
Given that CH is the angle bisector of angle DHG
m(GF) = (2x + 6)°
m(DC) = (7x – 1)°
m(DC) = m(GC) = (2x + 6)° [congruent angle]
The measure of half a circle is 180 degrees.
Therefore, we would have the following equation that would enable us find the value of x:
2[m(DC)] + m(GF) = 180°
Plug in the values
2(7x – 1)° + (2x + 6)° = 180°
14x – 2 + 2x + 6 = 180
Combine like terms together
16x + 4 = 180
16x = 180 - 4
16x = 176
Divide both sides by 16
16x/16 = 176/16
x = 11
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Answer:
-9 < x
Step-by-step explanation:
6x-11-13x<7-5x
Combine like terms
-11-7x<7-5x
Add 7x to each side
-11-7x+7x<7-5x+7x
-11 < 7+2x
Subtract 7 from each side
-11-7 < 7-7+2x
-18 < 2x
Divide by 2
-18/2 < 2x/2
-9 < x
