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Juliette [100K]
3 years ago
13

Find the length of the third side. If necessary, write in simplest radical form. V33 7

Mathematics
1 answer:
julsineya [31]3 years ago
7 0

Answer:

Step-by-step explanation:

pyrhagoras theorem

a^2+b^2=c^2

(\sqrt{33 )^2+b^2=7^2

33+b^2=49

b^2=49-33

b=\sqrt{16

b=4

therefore the length of the third side is 4

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Nicole used 3/8 of her ribbon to wrap the present. If she used 6 feet of ribbon for the present how much ribbon did Nicole have
lilavasa [31]
You would set up a proportion. 3/8 = 6/x... cross multiply ( 3*x = 3x and 6*8 = 48)  3x = 48... divide both sides by 3 (3x/3 = x and 48/3 = 16)

So, she originally had 16 feet of ribbon.
6 0
3 years ago
Anna made 20/28 free throws in basketball this season.To the nearest thousands,what is her free-throw average?
Afina-wow [57]

Answer:

0.714 free throws.

Step-by-step explanation:

Anna made 20 out of 28 free throws.

Free-throw average = \frac{20}{28}  = 0.7142857143 free throws.

This equals 0.714 free throws (answer rounded up to the nearest thousandths)

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3 years ago
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Neporo4naja [7]

Answer:

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6 0
2 years ago
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A car braked with a constant deceleration of 16ft/s2, producing skid marks measuring 200 feet before coming to a stop. How fast
Llana [10]

Answer:the car was traveling at a speed of 80 ft/s when the brakes were first applied.

Step-by-step explanation:

The car braked with a constant deceleration of 16ft/s^2. This is a negative acceleration. Therefore,

a = - 16ft/s^2

While decelerating, the car produced skid marks measuring 200 feet before coming to a stop.

This means that it travelled a distance,

s = 200 feet

We want to determine how fast the car was traveling (in ft/s) when the brakes were first applied. This is the car's initial velocity, u.

Since the car came to a stop, its final velocity, v = 0

Applying Newton's equation of motion,

v^2 = u^2 + 2as

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7 0
3 years ago
Find the balance on a deposit of $455 that earns 4% interest compounded annually for 2 years. $36.40 $491.40 $492.13 $819
STatiana [176]
A=P(1+ \frac{r}{n})^{tn}
A=future amount
P=present amount
r=rate in decimal
n=number of times per year compounded
t=time in years

given
P=455
r=4%=0.04
n=1
t=2

A=455(1+ \frac{0.04}{1})^{(2)(1)}
A=455(1+ 0.04)^{2}
A=455(1.04)^{2}
A=492.128
round
$492.13
3rd option
5 0
3 years ago
Read 2 more answers
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