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frosja888 [35]
4 years ago
7

still bought a t-shirt for $21 and a pair of shorts for $16 he paid with 20 bills how much money did Dale get back

Mathematics
1 answer:
Sphinxa [80]4 years ago
8 0
I would say three, because if you have $40 in 20 dollar bills, $21+$16=37. So then $40-$37=$3.
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7 0
3 years ago
4/5 m, if m = 10<br> HURRY!!
Ymorist [56]
8
(4/5)* 10= 8
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Hope this helps:)
6 0
3 years ago
Find the value of x<br><br> A. 7<br> B. 6<br> C. 8<br> D. 14
Anni [7]

x + 2 = 7, x is a variable, but we can work out its value if we try! A variable doesn't have to be "x", it could be "y", "w" or any letter, name or symbol.

8 0
3 years ago
The submarine is at a depth of -116 2/7 feet when the scientists detect a signal frequency from the ocean floor. They dive farth
Lady_Fox [76]

Answer: -64\frac{2}{7}\text{ feet}

Step-by-step explanation:

When the scientists detect a signal frequency from the ocean floor, then the depth of submarine =-116\frac{2}{7} feet

=-\frac{814}{7} feet

When they dive farther to check the signal, then the depth of the submarine=-180\frac{4}{7}=-\frac{1264}{7} feet.

The net change in their elevation =-\frac{1264}{7}-(-\frac{814}{7})

=-\frac{1264}{7}+\frac{814}{7}\\=-\frac{450}{7}=-64\frac{2}{7}\text{ feet}

5 0
4 years ago
Read 2 more answers
An auditorium with 52 rows is laid out where 6 seats comprise the first row, 9 seats comprise the second row, 12 seats comprise
ivanzaharov [21]
The number of seats per row generate an arithmetic sequence. Let a_n denote the number of seats in the n-th row. We're told that the number of seats increases by 3 per row, so we can describe the number of seats in a given row recursively by


\begin{cases}a_1=6\\a_n=a_{n-1}+3&\text{for }2\le n\le52\end{cases}

The total number of seats is given by the summation

\displaystyle\sum_{n=1}^{52}a_n

Because a_n is arithmetic, we can easily find an explicit rule for the sequence.

a_n=a_{n-1}+3
a_n=(a_{n-2}+3)+3=a_{n-2}+2\cdot3
a_n=(a_{n-3}+3)+2\cdot3=a_{n-3}+3\cdot3
\cdots
a_n=a_1+(n-1)\cdot3

So the number of seats in the n-th row is exactly

a_n=6+(n-1)\cdot3=3+3n

This means the total number of seats is

\displaystyle\sum_{n=1}^{52}a_n=\sum_{n=1}^{52}(3+3n)=3\left(\sum_{n=1}^{52}1+\sum_{n=1}^{52}n\right)

You should be familiar with the remaining sums. We end up with

\displaystyle\sum_{n=1}^{52}a_n=3\left(52+\dfrac{52\cdot53}2\right)=4290
3 0
3 years ago
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